Positively charged carbon atom of the aldehyde's carbonyl group attacks p-position of aniline, having a negative charge. Compound 1 forms, with a positive carbon attacking a p-position of another aniline molecule.
NH2-C6H5 + RC(O)H -> NH2-C6H4-CHR(OH) (compound 1)
NH2-C6H4-CHR(OH) + NH2-C6H5 -> NH2-C6H4-CH(R)-C6H4-NH2 + H2O
In case of formaldehyde, the product is 4,4'-methylenedianiline (MDA).
These compounds undergo a nucleophilic substitution reaction followed by an elimination, to produce an imine.http://www.mhhe.com/physsci/chemistry/carey/student/olc/ch22aldehydeskeytonesamines.html
The reaction mechanism of aniline with acetic anhydride is that it will attack. Aniline readily undergoes an electrophilic mechanism and will instantly react.
The reaction products are acetyl aniline and acetic acid C6H5-NH2 + (CH3CO)O = C6H5-NH-CO-CH3 + CH3-COOH
Acetic anhydride and aniline are the reactants for the preparation of acetaanilide.
If the excess acetic anhydride is not removed in the reaction vessel an unwanted reaction will occur. The acetic anhydride will react causing esterification.
No it is not among these.
glaycil-analil
CH3COOH = CH4 + CO2 or CH3COO + H
Acetic anhydride and aniline are the reactants for the preparation of acetaanilide.
The reaction is: (CH3CO)2O + H2O = 2 CH3COOH
If the excess acetic anhydride is not removed in the reaction vessel an unwanted reaction will occur. The acetic anhydride will react causing esterification.
Write a detailed set of equations for the acetylation reaction, and in particular show clearly that the reaction can be regarded as a nucleophilic substitution, in which the attacking nucleophile is aniline (attacking acetic anhydride).
Acetanilide
No it is not among these.
The formation of aspirin will proceed faster if acetic anhydride is used in place of acetic acid. However, acetic anhydride will hydrolyze in the presence of water to form acetic acid, slowing down the reaction.
glaycil-analil
CH3COOH = CH4 + CO2 or CH3COO + H
what is the chemical equation when phenol react with hydrochloric acid
it was prepared by using salycyclic acid when reacts with acetic anhydride in presence of sulphuric acid
The chemical reaction is:C6H5NH2 + (CH3CO)2O → C6H5NHCOCH3 + CH3COOH