This is hard to answer without being able to draw, but I will do my best!
First of all, each element needs 8 electrons (except hydrogen which only needs 2, i don't know why, it just does). A dash between two elements equals 2 electons. One element needs to be in the middle and the rest are on each side of it. Elements with the most electronegativity are almost always in the center ( just remember the ones closest to Fluorine are the strongest.).
Now how many electrons do we need total? Br is in the 17th group, so it has 7 valence electrons. C is in 14, so it has 4 valence electrons. H is in group 1, which means 1 electron. However, there are three of them, so there are three electron from H. Now, add them up. 7+4+3=14, which means there needs to be a total of 14 electrons. Now to start your drawing:
First of all, Br is closest to Fluorine, so it will be in the middle. Next, the Hydrogens should be put on 3 of the sides (it doesn't matter which sides). To make it less confusing, I will give the sides: up, down, left, and right. Put H on the "up", "left", and "right" sides of Br. Next, put the C on the "down" side. Draw one dash each for all the elements connecting to Br. H, being the weird element is done now. It only needs 2 electrons and the dash counts as 2. Now take a moment and count how many electrons have been used. you should have 4 dashes, which means 8 electrons have been used. 14-8=6. Now we have 6 more electrons to use. Put 2 dots each on the "left", "right", and "bottom" sides of C. Why? C still needs 6 more electrons because it "wants" a total of 8. Each dot is an electron. Now if you check the drawing, each H's should have 2 electrons each (1 dash each), the Br should have 8 electrons (4 dashes) and the C should have 8 electrons (1 dash, 6 dots).
Lol, that would have been SOOO much easier if I could just draw it out!! I hope I helped you understand how to do this in the future :) Also, I know it is right because I had this for homework the other day and I got it correct, just so you don't wonder if this is reliable or not ;) Good luck! (And if this is homework I hope you get the rest of them right!)
There is a single line between the H and Br and three lone pairs of electrons around Br.
.. I think it's H-Br: .. H has 1 valence electron and Br has 7. The Br has 2 dots on top, 2 after it and 2 dots under it. It doesn't show up like that when i typed it sorry.
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: Br :
: : :
:Br - B - Br :
: :
Basically 3 lone pairs on each Br. Three bonds, trigonal structure.
H : Z = 1 so one electron wich wants to meet another one
Br : Z = 35 so 3 "doublet non liants" and one free electron
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H-Br/
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There is a single line between H & Br & 3 pairs of dots (6 dots) around Br.
hydrogen carbon hydrogen 2(hydrogen twice which explains the two in the second H symbol) bromine learning this in class hope it helps!
H-Br with two lone pairs around Br
Increasing order of Lewis acidity BH3>BBR3>BCl3>BF3
lewis structure of Cl2O7
Lewis structure was created in 1916.
What is Lewis Structure for the bicarbonate ion
BBr3
Increasing order of Lewis acidity BH3>BBR3>BCl3>BF3
BBr3 itself is the molecular formula of Boron Tribromide.
lewis structure of Cl2O7
Lewis structure was created in 1916.
What is Lewis Structure for the bicarbonate ion
Yes, XeF4, or xenon tetrafluoride, has a Lewis structure.
First, it helps to draw out the Lewis structure. Boron, being the least electronegative element is in the center, with the three Bromines singly bonded around it. Each Br has an octet of electrons (3 lone pairs plus the single bond) and there are no electrons left over to go onto the Boron. This leaves Boron without an octet, but Boron is an exception to the octet rule so that's okay. So, no BBr3 does not follow the octet rule.
BBr3
No, not exactly. It is an ionic compound so it would not have a Lewis dot structure. However, the carbonate anion, CO3^2- does have a Lewis dot structure.
Potassium oxide (K2O) is an ionic compound, not a molecule, and does not have a Lewis structure.
Trigonal Planar
Formula: BBr3