Total electrons --> 7+42-1=48 Cl as a central atom One lone pair on Cl (on the side) 4 F's up and down and the other two on the opposite side of lone pair. F I :- Cl - F - F I F This is the best I can do with plain text.
The answer is +1 because the rule for oxidation numbers is that F is always -1
Also the oxidation numbers have to add up to zero.
In ClF3, the oxidation number of Cl would be 3+
-1 for each F, +4 for Cl
The oxidation number is 3+
-1 for F, +1 for Cl
Oxidation number of chlorine is +7. oxidation number of O is -2.
KCLO3 the oxidation number of potassuim is +1, oxidation number of chlorine is +5 the oxidation number of oxygen is -2 and there are 3 atoms of oxygen KClO3=1+5+(-2)3=0 therefore the oxidation number of KClO3 =0 or neutral
Oxidation number of N is +3. Oxidation number of Cl is -1.
S = +2 oxidation state cl = -1 oxidation state
The oxidation number of Na in NaCl is +1, while the oxidation number of Cl in NaCl is -1.
ClF3 exists but FCl3 does not because the Cl has vacant 3d orbits orbitals and can thus combine with three F atoms but F does not have any d-orbitals and thus it cannot show the oxidation state of +3 and bond to 3 Cl atoms.
Oxidation number of chlorine is +7. oxidation number of O is -2.
KCLO3 the oxidation number of potassuim is +1, oxidation number of chlorine is +5 the oxidation number of oxygen is -2 and there are 3 atoms of oxygen KClO3=1+5+(-2)3=0 therefore the oxidation number of KClO3 =0 or neutral
Oxidation number of N is +3. Oxidation number of Cl is -1.
S = +2 oxidation state cl = -1 oxidation state
as oxidation number of K is 1 and the molecule is neutral 1+ Cl=0 Cl= -1 Therefore, the oxidation number of Cl is -1
The oxidation number of Na in NaCl is +1, while the oxidation number of Cl in NaCl is -1.
the oxidation number of the molecule HCl is 0.because H has Oxidation no +1 and Cl has -1 oxidation no in the HCl.
Ag +1, Cl -7
+1 for Li and -1 for Cl
-1 for each Cl +3 for N
-1 for each Cl, +2 for Pt