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Well if it any substance such as water or steel it called the objects specific heat waters is 4180 (joules/( kilogram•Kelvin)
specific heat
It is not the heat of a substance. The specific heat, Cp, is the energy required to raise the temperature of a gram of the material one degree Celsius at a constant pressure.

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11y ago
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13y ago

For this Physics question, you should follow the formula of Q=mcΔT

Where:

Q is equal to the amount of energy required to raise the substance's temperature by either 1 Kelvin or 1 Degrees Celsius (measured in Joules [J] )

c is equal to the specific heat capacity, which is the amount of energy required to raise the temperature of 1kg of substance (measured in J kg -1 )

m is equal to the mass of the substance (measured in kilograms [kg] )

ΔT is equal to the change in temperature (measured in either Degrees Celsius [˚C] or Kelvin [K] )

So for the example given, we want to figure out the heat energy required (Q). Let us write out all the information we do know:

c of water is equal to 4180 J kg -1 when in liquid form

m of the water is equal to 1 gram which is equal to 0.001 kg

ΔT of the water is equal to a 1˚C temperature change

Therefore, Q=mcΔT goes to:

Q=0.001 x 4180 x 1

Q=4.18 J

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12y ago

It varies depending on the substance. The value is called specific heat.

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14y ago

1.00 cal/g-oC: that means that 1.00 calorie (4.184 Joule, 0.00397 BTU) is needed to raise 1g (0.0022 lb) of water 1oC (1.8ºF)

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12y ago

One calorie.

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14y ago

specific heat capacity

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13y ago

1 calorie

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8y ago

one calorie

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Q: What is the needed heat to change the temperature of one gram of water by one degree Celsius?
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