This might help you. First and foremost is the information the manufacturer puts on the nameplate of the motor. Second, the generic amperage can be found on motor charts that are on the internet. Third you can use a formula to find the approximate amperage. HP = Amps x Volts x 1.73 x %Eff x pf/746. Transposed for Amperage, Amps = HP x 746/Volts x 1.73 x %Eff x pf. Use power factor = .9. Eff = 746 x Output HP/Input watts use 1.5. For estimating a 400 HP motor running on 480 volts. Amps = 400 x 746/ 480 x 1.73 x 1.5 x .9 = 298400/747.36 = 399.27 amps. See how much easier it is to read the nameplate.
In this example, we must realise that the 400 hp represents the rated output power of the machine. To determine the load current, we must first determine the rated input power and, to do this, we need to know the full-load efficiency, which we are not given. So, let's assume that this particular machine has an efficiency of, say, 87%. So we must convert the output power in horsepower to the output power in watts, and divide that figure by 0.87, giving us a rated input power of 443 kW.
The next thing we must understand is that, for a three-phase supply, the quoted value of supply voltage is normally the line voltage (never the phase voltage).
The equation for the power of a balanced three-phase load (motors are always 'balanced' loads) is as follows: power = 1.732 x line voltage x line current x power factor.
Again, we are not given a full-load power factor, so we need to assume a value -in this case, let's assume that it's, say, 0.7.
So we can now determine the line current to the motor:
line current = (rated input power) / (1.732 x line voltage x power factor)
line current = 443 000 / (1.732 x 480 x 0.7) = 760 A(Answer)
Taking the motor at an efficiency of 90% and a power factor of .9 the motor will draw 58 amps.
24 amps. This could be three 11.54 resistors connected in star, or three 34.6 ohm resistors connected in delta.
106 amps
At 240v single phase it's 70.8 amps. If it runs on 2 wires plus ground, take the voltage rating of the equipment and divide that into the watts to get amps. At 480v 3 phase it's 25.8 amps. At 208v 3 phase it's 47.2 amps. <<>> There are zero amps in 14 kW. A voltage needs to be stated. I = W/E, Amps = Watts/Volts.
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%
There is not enough information provided to answer. KVA is short for "Kilo Volt Amperes". That is, thousands of Volt Amps. In order to determine how many Amperes are flowing, you must know at what voltage it is operating. Amperes = 45,000 ÷ volts Bill Slugg
50 Amps Single Phase 20 Amps Three Phase
180 amps. Assuming the panel will be loaded only 80%.
For a single phase 3 HP motor at 208 volts the amperage is 18.7 amps. For a three phase 3 HP motor at 208 volts the amperage is 10.5 amps. This figure is derived at by taking the full load amps at 230 volts and adding 10%. As the voltage goes down the amperage goes up. For 200 volt motors 15% is added to the FLA of a 230 volt motor.
It means 225 amps on each phase.
24 amps. This could be three 11.54 resistors connected in star, or three 34.6 ohm resistors connected in delta.
106 amps
9
About 3 amps, maybe slightly less.
8,33 Amps
The answer is that it depends upon the a. efficiency (to determine its input power). b. supply voltage. c. nature of the supply (single-phase, three-phase, d.c., etc.)
62.5 amps
50 amps.