What is the equation for the reaction of sulfurous acid and sodium hydroxide?

Answer 1

Step 1: Write the balanced "molecular" equation:

H2S + 2 NaOH Na2S + 2 H2O

Step 2: Consult the solubility and strong electrolyte rules linked above to determine whether each substance will dissociate:

H2S+

2 NaOH

Na2S+2 H2O

no

yes

yes

Step 3: Dissociate all soluble salts, strong acids, and strong bases (except calcium hydroxide). Leave together all "not soluble" salts and weak acids or bases:

H2S (aq) + 2Na+ (aq) + 2OH- (aq) 2Na+ (aq) + S2- (aq) + 2 H2O (l)

Step 4: Cross out "spectator ions" that appear on both sides of the reaction (these ions do not participate in the chemistry) and rewrite the "net" reaction using the smallest possible coefficients.

H2S (aq) + 2OH- (aq) S2- (aq) + 2H2O (l)

Answer 2

it is going to be 2 H+ (aq) + 2 OH-1 (aq) ----------> 2 H2O (L)
which at the end could simplify to
H+ (aq) + OH -1 (aq) -------------> H2O (L)


I hope this helped

Answer 3

H2SO4+2NaOH --> NaSO4+2H20

Answer 4

H2SO4 + 2 NaOH => Na2SO4 + 2 H2O.

Answer 5

H+(aq) + OH-(aq) --> H2O(l)

Answer 6

2NaOH + H2SO3 = Na2SO3 + 2H2O