2KBr + Cl2 ----> 2KCl + Br2
2K+Cl2------->2KCl
Potassium + Chlorine --> Potassium Chloride (potassium plus chlorine arrow potassium chloride)
2KI + Cl2 = 2KCl + I2
you have to write... 2KI + Cl2 = 2KCl + I2
2KI + Cl2 = 2KCl + I2
2K + Cl2 ---> 2KCl
2K+Cl2------->2KCl
It is impossible to balance that equation.
Potassium + Chlorine --> Potassium Chloride (potassium plus chlorine arrow potassium chloride)
2KI + Cl2 = 2KCl + I2
you have to write... 2KI + Cl2 = 2KCl + I2
2KI + Cl2 = 2KCl + I2
The balanced equation for copper(II) oxide and potassium chloride is CuO + 2KCl → CuCl2 + K2O When copper(II) oxide reacts with potassium chloride then it forms copper(II) chloride and potassium oxide.
KCl will not decompose
2 K + Cl2 = 2 KClOxygen is not needed.
potassium iodied = KI chloride = cl
4KClO3= 3KClO4+KCl