The bond order of C2 in this excited state is 1/2 (6-2) = 2. There are six bonding electrons and two antibonding electrons.
There is a bond order of 1 for B2.
This compound has a bond number of 1.
2.5
2.5
2
It's 3.
Butyne has 4 carbons and a triple bond. The triple bond can be between C1 and C2, or C2 and C3 so there are 2 different "forms" or isomers of butyne.
2
C2 does not follow the VSEPR theory here. Carbon cannot have lone pairs and quadruple bonds do not exist. C2 DOES however exist. It has a bond order of 2 and it exists in the gas phase.
In Chemistry, C2 is the symbol for Diatomic Carbon.
C2h2+ 2h2 = c2h6
Butyne has 4 carbons and a triple bond. The triple bond can be between C1 and C2, or C2 and C3 so there are 2 different "forms" or isomers of butyne.
Organic compounds can have carbon-carbon double bonds.
2
C2 does not follow the VSEPR theory here. Carbon cannot have lone pairs and quadruple bonds do not exist. C2 DOES however exist. It has a bond order of 2 and it exists in the gas phase.
Here~ D2 D2 D2 B D2 C2 B A C2 C2 C2 A C2 B A G D2 D2 D2 G G A B C2 C2 C2 C2 D2 C2 B A G D2 D2 D2 B D2 D2 D2 B D2 D2 D2 E2 D2 D2 B C2 C2 C2 A C2 C2 C2 A C2 C2 C2 B2 C2 B A G
12c
A c2 c2 c2
No until recently it was believed that the maximum was a triple bond. However recently (2012) a team have done calculations on C2 molecule which appears to show that there is a weak fourth bond present. I suspect this debate will rumble on in academia.
No, carbon is unable to form four mutual covalent bonds with itself. While bonding of this type is seen with the transition metals, it is due to the hybridisation of the d orbitals, which are inaccessible to carbon electrons in the ground state. This being said, C2 molecules do exist. Carbon atoms hold four electrons in their valance (p) orbitals, and so eight are contributed to the bonding regime in C2. Six of these adopt bonding energy levels in the C2 molecule (forming three covalent bonds), while the other two are forced into the antibonding mode, effectively cancelling out the bonding effects of one of the other pairs, giving a diatomic molecule with bond strength consistent with a double covalent bond.
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In order to have a hypotenuse, the triangle must be a right triangle - in this case we have an isosceles right triangle. Using the Pythagorean theorem: a2 + b2 = c2 152 + 152 = c2 225 + 225 = c2 450 = c2 c = √450 c = √2*9*25 c = 15√2