What is the center points of an parabolas equation?

Center Point, the place in Linn County, Iowa, USA

y= ax2+bx+c

(y - 3) = a(x - 1)2 y = a(x - 1)2 + 3 4 = a(4 - 1)2 + 3 1 = 9a a = 1/9 y = 1/9 (x - 1)2 + 3

Since the vertex of the parabola is at the point (6, 1.5) and the point (7, 3.5) is on the parabola, the point (5, 3.5) also is on the parabola (since the axis of symmetry is x = 6). So we have: y =...

Let the polynomial be y = ax^2 + bx + c The derivative or slope at the minimum is zero: 2ax + b = 0We have 55 = a (4^2) + b (4) + c25 = a (3^2) + b (3) + cand 2a(3) + b = 0 or b = -6a55 = 16a - 24a +...