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pOH = -log[OH-] = -log(5*10^-3) = 2.3

pH = 14 - pOH = 14.0 - 2.3 = 11.7 (at 25 oC)

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9y ago
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11y ago

pH + pOH = 14.

So pOH = 14 - 5.33 = 8.67

pOH = -log[OH-]

[OH-] = 2.14 x 10-9 M

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13y ago

In a solution of pH 5, the concentration of OH- ions is 10-9 moles per liter.

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12y ago

Use this (at 25oC) : [OH-] = 10-(14-pH) ,

so:

[OH-] = 10-(14-5.75) = [OH-] = 10-8.25 = invlog(-8.25) = 5.6*10-9 mol/L

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14y ago

The solution of Acetic acid as vinegar.

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7y ago

The pOH is 8,7.

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15y ago

3.3

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13y ago

acidic

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Q: What is the OH- of a solution with pH 5.75?
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