W= Fd Work Done (J) = Force (N) x Distance (M)
Work = Force x Displacement x cos(θ) where θ is the angle between the direction of the Force and the direction of the displacement
As Force and displacement are both vectors and work is a scalar, the magnitude of the work is the scalar product of force and displacement
W = F.s
W = Fs cos(θ)
In order to simply determine work done on an object, figure out how much force was exerted on the object, and over what distance, and multiply them. If you are just pushing an object, figure out the force needed to overcome friction and how far it was pushed. The unit of work (and energy) most commonly used is the joule. It is one Newton of force applied over one meter. 2 joules could be one Newton pushed over 2 meters, or 2 Newtons pushed over 1 meter.
Work= force(N) x distance(M) or W=fd
work = (force) (distance)
To be totally correct, work is the dot product of the force and distance. Since force and distance are both vectors the angle between them is important. If force and distance is in the same direction then the formula
work=(force)(distance) is correct. Otherwise
work=(force)(distance)(cos(theta))
THE FORMULA IS W=FD W BEING WORK
F BEING FORCE D BEING DISTANCEHOPE THAT HELPED SOME
This is the general formula for work, without going into specifics:
Work = (Force)(Distance) (cosine of the angle between force and distance)= the change in kinetic energy
If you wan some specifics just holler.
Work = Force x Distance; force is in newtons, distance is in meters
The unit for work is Nm (newton Meters)
To calculate useful work done, one could use an efficiency formula. Simply put, it is W= Fd. Work Done (J) = Force (N) x Distance (M) Work = Force x Displacement x cos.
Formula=work all ofar time taking
w=fd
To calculate work done on an object one needs to use the following equation; work = force x distance or W = F x d
To calculate 200 J of work in 20 seconds would be to calculate the power. You would use the equation power equals work divided by time. This gives you 10 W of power.
I believe the answer is 35%. Since the formula for energy = useful work / total work input, you would then plug 35 j into the useful work and 100 under the total work input. You divide that and you get .35. Then, you multiply .35 by 100, and you get 35%.
No. Only when there is also movement. The basic formula for work is: work = force x distance If a certain force is applied along a certain distance, then work is done.
According to the formula, Work done = Force . Displacement So, 200(10) 2000 joules. Hence, the work done by the person will be 2000 joules.
efficiency formula is (Wout/Win)*100% Wout is the work done by the machine is called the output work Win is the work done by you on a machine is called the input work efficiency= useful work output/work input For science, the effiency is: AMA/IMA * 100
You would have a very tough time, because that isn't the formula to calculate work. (distance) divided by (time) is the formula to calculate speed. The formula to calculate work is: (force) multiplied by (distance).
The equation to calculate the work done is: Work done (J) = force applied (n) x distance moved of force (m)
(work out/work in) x 100
Work Output=Resistance X Distance
Work = (force) x (distance)
To calculate work done on an object one needs to use the following equation; work = force x distance or W = F x d
W=Fdf=ma
Not very long at all. W=-.5k(x-xo)2 That I believe is the formula to calculate the amount of work done, I have no idea how to calculate the time it would take for that to go to zero but that formula may bring you closer to the soln.
The answer depends on what information you have.
Not enough information. You can calculate the work (using the formula for potential energy), but to calculate the power, you would also need the time (how fast is this done?)
i don't know so ha ha