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The hybridization is sp3 because N is bonded to 3 hydrogen groups and contains two unpaired electrons. For these three bonds and unpaired electron the s orbital and three p orbitals hybridize forming __ __ __ __ sp3 hybridized orbitals.

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14y ago
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10y ago

Remember this refers only to valence shell electron configuration. Nitrogen has two sp hybridized orbitals and two degenerate p orbitals; one sp orbital is participating in a sigma bond with the Carbon atom's sp hybridized orbital and the other houses a lone pair of electorns. The two p orbitals each contain a single electron which partake in pi bonds with 2 unpaired p orbital electrons of the Carbon atom.

tl;dr

Both Carbon and Nitrogen are sp hybridized

Nitrogen

1)sp N sigma bonds with sp C

2) spN (lone pair of electrons)

3) pN (unpaired electorn) pi bonds with pC (unpaired electon)

4) pN (unpaired electorn) pi bonds with pC (unpaired electron)

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10y ago

Hybridisation is a first step in producing orbitals with the right orientation for covalent bonding. In something like the nitride ion the electrons will be in the 2s and 2p orbitals as in Neon.

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15y ago

It's linear---it's hybridization has to be sp.

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12y ago

sp

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13y ago

sp3

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Q: What is the hybridization of nitrogen in NF3?
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