sp3d2
sp3d2
sp^3d^2
If the given compound exists, there'll be 4 sigma bonds and a single remaining electron in the valence shell of the central atom. With 5 activation groups, the hybridization would be sp3d.
sp2. Even though there is a double bond the hybridization will be sp2 (with the pi-bond considered non-hybridized)
The valence electrons of O is 6 and F is 7. 7x2= 14 + 6 =20 electrons in totalEach Fluorine makes a single bond with the oxygen atom. so that's 2 bonds right there.then fill up the fluorines so that they are satisfied. 16 electrons have now been used up. But the oxygen atom is still unsatisfied so you must give the oxygen atom 2 lone pairs. the total is now 20 electronsnow the hybridization of the oxygen atom which in this case is the central atom is determined by adding the total # of bonds together, it has 2 bonds with Fluorine and two lone pairs, add them up and u get 4 total bonds. 4 total bonds is = to sp^3
sp3d2
sp^3d^2
If the given compound exists, there'll be 4 sigma bonds and a single remaining electron in the valence shell of the central atom. With 5 activation groups, the hybridization would be sp3d.
sp2. Even though there is a double bond the hybridization will be sp2 (with the pi-bond considered non-hybridized)
In icl3 central atom is iodine and its valency is 7 out of 7 electrons 3 electrons are in chemical bonding so 2 lone pairs are there. Hybridization = number of sigma bonds + number of lone pairs = 3 sigma bonds + 2 lone pairs = 5 = sp3d ( 1 s + 3 P + 1 d = 5 ).
The valence electrons of O is 6 and F is 7. 7x2= 14 + 6 =20 electrons in totalEach Fluorine makes a single bond with the oxygen atom. so that's 2 bonds right there.then fill up the fluorines so that they are satisfied. 16 electrons have now been used up. But the oxygen atom is still unsatisfied so you must give the oxygen atom 2 lone pairs. the total is now 20 electronsnow the hybridization of the oxygen atom which in this case is the central atom is determined by adding the total # of bonds together, it has 2 bonds with Fluorine and two lone pairs, add them up and u get 4 total bonds. 4 total bonds is = to sp^3
sp3 is the hybridization of the nitrogen atom in NCl3.
sp3 , 2 lone pairs, 1 single bond to the oxygen, 1 double bond to oxygen
PBr2 is also known as Phosphorous Bromide. The P is the Phosphorous element and the Br is the Bromine element. The 2 beside the Br means that there are 2 Bromine elements.... There, PBr2 is one phosphorous and 2 bromine elements. hope this helps....
SF6 sp3d2H2S sp3ICl3 sp3dBF3 sp2CS2 sp
sp2,trigonal, bent
The geometry is octrahedral.