0
In order to compute that integral, we need to use the power rule:
∫ xⁿ dx = xn + 1/(n + 1) + c where n is any constant except 0 and -1.
Apply that rule to get:
∫ 3x dx
= 3 ∫ x dx [Factor out the constant]
= 3 ∫ x1 dx [Make note of the exponent]
= 3x1 + 1/(1 + 1) + c
= 3x2/2 + c
So that is the integral of 3x.
Wiki User
∙ 11y ago
Emy Bella Kuang Luo
∫ xⁿ dx = xn + 1/(n + 1) + c where n is any constant except 0 and -1.
Apply that rule to get:
∫ 3x dx
= 3 ∫ x dx [Factor out the constant]
= 3 ∫ x1 dx [Make note of the exponent]
Mabel Predovic
Wiki User
∙ 11y ago∫ -3x dx = -3/2 x2 + c
Jonathan Zhu
Urmom'sTHICC.
Anonymous
oml dis is hard im dieing from dis math
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Integral of -3 dx?
-3x
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Integral of 3 raised to x?
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What is the integral of -3dx?
∫(-3)dx = -3x + C
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Integral of 3x-2 dx?
5
Determine the integral 3x minus1 x plus 2dx?
Int[3x-x+2] =Int[2x+2] =x^2 +2x +C
How do you integrate a number in respect to x?
multiply the number times x. For example, the integral of 3 is 3x.
