Lead (II) iodide
Transition metals always need roman numerals to represent their charges.
There is no such thing as PbCI4
but PbCl4 (with an L, not an I) is lead IV chloride.
Lead IV (Four) Iodide
Lead I iodide
Lead 4 Iodide
Lead II iodide.
lead(IV) iodide
This compound is lead(IV) sulfate.
PbI4Lead iodide========
The chemical formula is PbI4.Pb(4+) + 4 I-
Lead (II) iodide is PbI2. Lead (IV) iodide is PbI4.
PbI does not exist. There are, however PbI2 and PbI4. Neither are good electrolytes.
Lead iodide is not a correct name. Lead is a transition metal and can form more than one ion. The charge of the lead ion should be in the name. For example, lead(II) iodide, which would be PbI2. Lead(IV) iodide would be PbI4.
PbI4Lead iodide========
The chemical formula is PbI4.Pb(4+) + 4 I-
Lead (II) iodide, which has PbI2 as its chemical formula, exists only this way and not in the form PbI4 as someone might guess. Though lead has a +2 and a +4 for its oxidation states, iodine is too weak an oxidizer to form the second lead-iodine compound. This stuff is toxic because of the lead, and you can read more about it by using the supplied link to the Wikipedia article.
Lead (II) iodide is PbI2. Lead (IV) iodide is PbI4.
Lead (II) iodide is PbI2. Lead (IV) iodide is PbI4.
PbI does not exist. There are, however PbI2 and PbI4. Neither are good electrolytes.
It is very slightly soluble in water.In a saturated solution:[Pb2+] = 1.2x10-2 mol/L[Br-] = 2.4x10-2 mol/Lbecause [Pb2+]*[Br-]2 = Ks = 6.3*10-6 and [Br-] = 2*[Pb2+]
Lead iodide is not a correct name. Lead is a transition metal and can form more than one ion. The charge of the lead ion should be in the name. For example, lead(II) iodide, which would be PbI2. Lead(IV) iodide would be PbI4.
It is a compound.
mixture
An ionic compound is an example of a chemical compound.
It is a compound.