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What is the kinetic energy of a 30 gram bullet that is traveling at 200 m s?
Wiki User
â 11y ago
Kinetic energy = 0.5.m.v2
unit m = mass [=] kg
v = velocity [=] m/s
Gryazev-Shipunov GSh-30-2 firing 30 × 165mm bullet, bullet mass is 0.4 kg with velocity of 880 m/s
Help your self press the calculator for the kinetic energy.
Unit calculate is in Joules
Wiki User
â 13y ago
Wiki User
â 12y agoKinetic energy = (1/2) (mass) (speed)2
The kinetic energy of the bullet is (1/2) (0.03) (200)2 = 600 joules.
While it's in flight, it's not doing any work. (Except for plowing through the air,
which we customarily ignore when we work Physics problems at this level.)
When the bullet finally meets its mark, it'll come to rest inside the target, and
its kinetic energy will be zero. Since energy is never created or destroyed, we
want to know what happened to the 600 joules. The answer is that the bullet
transferred that energy to the target, and 600 joules of energy, or 'work', were
instantly dispersed throughout the target's clothing, flesh, bone, and fluids.
yuk
Wiki User
â 11y agoKE = 1/2mv2, where m is mass in kg and v is velocity in m/s.
mass of bullet in kg = 0.030kg
KE = 1/2mv2 = 1/2(0.030kg)(200m/s)2 = 600 kg•m2/s2 = 600 N•m = 600 Joules
Wiki User
â 13y agoEk = 0.5mv**2
0.5*0.03*200**2
0.015*40000
600 = Ek
600 J
Ash
KE = œmv² = œ(0.030 kg)(200 m/s)² = 600 J
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