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What is the likelihood that two individual heterozygous for a mutation will have a child who expresses that genetic defects?

Answer:
there is a 1/4 chance that the offspring will have two dominant genes for that effect, a 2/4 chance that they will be heterozygous like their parents and a 1/4 chance that they will have two recessive genes. If this mutation is the recessive, then the likelihood of the offspring expressing will be 1/4
First answer by ID1165737938. Last edit by ID1165737938. Question popularity: 1 [recommend question].

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