assume acceleration at surface = 9.81(m/s)/sassume radius to surface from cog = 6 371 000 meters (r)your distance from cog = ? meters (d)then :a=9.81/(d/r)^2)
9.8 meters (32.2 feet) per second2
9.8 m/s squared
Generally it depends on the mass of the object as well as the location of the object because both can make different equations. As per as it is censored the force applied by the earth due to its...
It would vary depending on distance from the surface and the density of the matter under the surface.