mass (g) = atomic wight / Avogadro's number
Avo = 6.022x10^23
10.81g This is found by looking at the atomic weight. The atomic weight refers to the mass of a singe atom in units of AMU (atomic mass units) and it also refers to the mass of one mole of the element in grams.
35.5 grams per mole or 5.90*10^-23 for a single atom
The periodic table states that the molar mass of copper is 63.546 grams per mole. That means that if you have one mole of copper, it will weigh 63.546 grams. One mole is 6.022x1023 (Avogadro's number) atoms. To find the mass of one copper atom in grams, you simply divide copper's molar mass by the number of atoms in one mole. 63.546 / 6.022x1023 = 1.055x10-22 One atom of copper weighs 1.055x10-22 grams.
BF3 - Boron trifluoride
32 grams, you can find the mass of one mole of any element by looking at its atomic mass eg chlorine has Atomic mass of 35.5 so the mass of one mole of chlorine is 35.5 grams.
10.81g This is found by looking at the atomic weight. The atomic weight refers to the mass of a singe atom in units of AMU (atomic mass units) and it also refers to the mass of one mole of the element in grams.
5
what is the atomic mass of an element : atomic mass is equal to the number of protons and number of neutrons present in an element
5 protons in one atom of boron. look at the periodic table.
1.00*10-7 moles of boron is how many grams is this
35.5 grams per mole or 5.90*10^-23 for a single atom
The periodic table states that the molar mass of copper is 63.546 grams per mole. That means that if you have one mole of copper, it will weigh 63.546 grams. One mole is 6.022x1023 (Avogadro's number) atoms. To find the mass of one copper atom in grams, you simply divide copper's molar mass by the number of atoms in one mole. 63.546 / 6.022x1023 = 1.055x10-22 One atom of copper weighs 1.055x10-22 grams.
BF3 - Boron trifluoride
32 grams, you can find the mass of one mole of any element by looking at its atomic mass eg chlorine has Atomic mass of 35.5 so the mass of one mole of chlorine is 35.5 grams.
The mass of an avogadro number of atoms in grams is numericaly equivalent to the amu mass of the atom. 6.023 * 10^23.
Approximately 2 / (6.022 x 1023) = 3.32 x 10-24 grams
There are exactly three electron pairs attached to the Boron atom, each one of them bonded to a chlorine atom as well.