What is the minimum volume of a 2.81 m naoh solution needed to make 150.0 ml of a 0.800 Mnaoh solution?

Answer 1

Let the asked volume (not minimum but exactly) be V1 mL,

then V1*C1 = V2*C2,

so V1 = [150 (mL) * 0.800 (mol/L)] / [2.81 (mol/L)] = 120/2.81 = 42.7 mL of the 2.81 M NaOH solution