The molar mass of MgCl2 = 95.211 g/mol
the molar mass is basically 20 for Ca and Br is 35 X 2 = 90
1 mole MgBr2 = 184.113g MgBr2
7mol MgBr2 x 184.113g MgBr2/mol MgBr2 = 1288.791g MgBr2
Molar mass of Mg is 24 and of Br is 80.
Hence, molar mass of MgBr2 is 24 +2 x 80=184g
1 mole MgBr2 = 184.113g MgBr2
278.17
The answer is 5,978 moles.
The chemical formula of magnesium dibromide is MgBr2.
To find the molarity of the substance, divide the moles of the substance by the volume of the solution in liters. First, calculate the moles of magnesium bromide: Convert grams to moles by dividing the given mass by the molar mass of magnesium bromide (184.1 g/mol). Moles of magnesium bromide = 4.13 g / 184.1 g/mol = 0.0224 mol. Next, divide the moles by the volume of the solution in liters: Molarity = 0.0224 mol / 845 L ≈ 0.00003 M (rounded to 3 significant figures).
Atomic mass of Sulphur is 32 1 mole = Atomic mass of sulphur No. of moles = Given mass/ Atomic mass No.of moles= 5/32 0.15 moles
number of moles = mass of the material/molar mass
The answer is 5,978 moles.
2.50 g MgBr2 x 1 mole MgBr2/184 g x 2 mole Br/mole MgBr2 = 0.0272 moles Br^-0.0272 moles Br^- x 6.02x10^23 anions/mole = 1.6x10^22 anions
Mass of 1mole of Argon is 39.95g. So, The mass of 7 moles of Argon is 39.95x7= 279.65g.
One formula unit of MgBr2 has three ions; one Mg2+ ion and two Br- ions. One mole of MgBr2 formula units has one mole of Mg2+ ions and two moles of Br- ions, for a total of three moles of ions.
The chemical formula of magnesium dibromide is MgBr2.
2.03mol
To find the molarity of the substance, divide the moles of the substance by the volume of the solution in liters. First, calculate the moles of magnesium bromide: Convert grams to moles by dividing the given mass by the molar mass of magnesium bromide (184.1 g/mol). Moles of magnesium bromide = 4.13 g / 184.1 g/mol = 0.0224 mol. Next, divide the moles by the volume of the solution in liters: Molarity = 0.0224 mol / 845 L ≈ 0.00003 M (rounded to 3 significant figures).
The mass of 7 050 moles of natural uranium is 238,02891 x 7 050.
Total mass of MgBr2- 36.9 g Mass of Br 32.0 / total mass 36.9 = .867 = 86.7% Mass of Mg 4.9 / 36.9 = .133 = 13.3% There is 86.7% of Bromine and 13.3% of Magnesium in the compound MgBr2
Number of moles = Total mass/Molar mass
Since molar mass of hydrogen is 1g , the no. of moles = mass of hydrogen given. or No. of moles= Given mass of substance/Molar mass of substance
Atomic mass of Sulphur is 32 1 mole = Atomic mass of sulphur No. of moles = Given mass/ Atomic mass No.of moles= 5/32 0.15 moles