If I understand the question correctly %Salt=mass salt/(mass salt+Mass water) *100
If these are known all is well... Measure your salt and water on a scale and input the results for the %
There is not enough information to answer the question. It depends on the salt concentration.
Evaporate the water and let the salt dry completely. Then determine the mass of the salt.
There are many ways to measure concentration, but the most useful is Molarity, the number of moles of the solute divided by the volume (in Liters) of the solvent. For instance, a 1M salt solution contains 1 mole of salt in 1L of water.
Because of the Law of Conservation of Mass, 5g salt dissolved in 100g of water has a mass of 105g.
The salt is held in solution and so adds to the mass.
Because the one with more mass has more salt in it. At 25º C 100 ml of water can dissolve 36 g of NaCl, maximum. You could make salt water with any amount of salt less than the maximum.
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Mass solution=100g Mass solution=20g Mass Mass % = (mass Of solute/mass Of solution ) x 100. =(20/100)x100 =1/5 x 100. =100/5 =20%
The mass of salt reclaimed should be the same as the mass of salt that was put into the solution.
The percent concentration is 13,75 %.
Only by experiments. For example the solution is heated, water is evaporated and the salt weighed.
13,75 % NaCl
There are many ways to measure concentration, but the most useful is Molarity, the number of moles of the solute divided by the volume (in Liters) of the solvent. For instance, a 1M salt solution contains 1 mole of salt in 1L of water.
A mass of salt and water solution that has been left in a warm place for a long time becomes brine, and then eventually it becomes salt, because the water evaporates.
489 grams
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
0.1 N iodide would be 0.1 moles of the iodide salt (e.g. KI) per liter of solution. For 500 ml, you would need 0.05 moles of the iodide salt. You need to state the salt (KI, NaI, LiI, etc.) in order to determine the actual mass required.
Because of the Law of Conservation of Mass, 5g salt dissolved in 100g of water has a mass of 105g.
The salt is held in solution and so adds to the mass.