2NaOH + H2SO4 = Na2SO4 + 2H2O
Ionic Equation
2Na + 2OH + 2H + SO4 = 2Na + SO4 + 2H2O
Cross out common elements and compounds on both sides to get the ionic equation:
2OH + 2H = 2H2O
H2SO4+2NaOH----->Na2SO4 +2H20
REMEMBER THE VALENCIES pls xD
Cu 2+ + SO4 2- + 2Na+ + 2OH- ---> 2Na+ + 4SO4 2- + Cu 2+ + 2OH-
2NaOH + H2SO4 --> Na2SO4 + 2H2O
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NH4+ + OH- --> (NH3)g + H2O
OH- + H+ --> H2O(l)
haha
H+ + OH- = H2O
H+ + oh- ---> h2o
Hf + oh- ---> f- + h2o
Molecular equation: H2SO4 + 2NH3 ---> (NH4)2SO4 Complete ionic equation: 2H++ SO42- + 2NH3 ---> 2NH4+ + SO42- Net ionic: 2H+ + 2NH3 ---> 2NH4+
2koh + h2so4 --> k2so4 + 2h2o
H+ + OH- = H2O
H+ + oh- ---> h2o
Hf + oh- ---> f- + h2o
F=mv2+3 try it very useful equation
Molecular equation: H2SO4 + 2NH3 ---> (NH4)2SO4 Complete ionic equation: 2H++ SO42- + 2NH3 ---> 2NH4+ + SO42- Net ionic: 2H+ + 2NH3 ---> 2NH4+
2koh + h2so4 --> k2so4 + 2h2o
2NaCl + Zn(OH)2
The net ionic equation for NaOH and Na2SO4 when they form a precipitate is simple. It will contain only the atoms that participate in the reaction. Both of these compounds are soluble.
The chemical equation is:Mg+ + 2 OH- = Mg(OH)2(s)
H2C4H4O6(aq)+2OH−(aq)→C4H4O62−(aq)+2H2O(l)
The net ionic equation that describes the reaction when these solutions are mixed is the net summation. This is the net ionic equation for the chemical reaction.
Ca2+ + 2OH- + 2H+ + SO42- -------> 2H2O + Ca2+ + So42- 2OH- + 2H+ -------> 2H2O