Any number that you like. Given any number at all, it is possible to find a polynomial equation of order 5 that will generate the above five numbers as the first five terms in a sequence as well as the chosen number as the sixth term.
Using the following polynomial of order 4, the next number is 841.
Un = (24x4 - 229x3 + 822x2 - 1127x + 576)/24 for n = 1, 2, 3, 4, ...
11
The nth term in this sequence is 4n + 3.
If you mean: 15 11 7 3 then the nth term is 19-4n
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
It is: nth term = 5-4n and so the next term will be -19
The nth term is 4n-1 and so the next term will be 19
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
The nth term is: 3n-7 and so the next number will be 11
The nth term of the sequence is 2n + 1.
The nth term of the sequence is (n + 1)2 + 2.
The nth term is: 3n-7 and so the next number will be 11