Na is +1 because it is a metal, and its charge is its oxidation number
O is -2 it is more electronegative than Cl, so it takes the electrons (6-8=-2)
Cl is +3 need to make the whole thing neutral (-2*2=-4 -4+1=-3... Cl has to balance it out.)
First a couple quick definitions: # The sum of all oxidation states in a neutral molecule is always zero # Oxygen always has an oxidation state of -2 # Sodium (Na) almost always has an oxidation state of +1 So for NaClO we have: 1+X-2=0 where X equals the oxidation state of chlorine. Solving for X we see that the oxidation state of chlorine is one X=2-1 X=1 For NaClO2 remember that each atom is counted individually so we will need to subtract both oxygens. 1+X-2-2=0 X=3 Hopefully you should be able to figure out the rest.
+1 for H
-2 for each O
+7 for Cl
+1 for H, -2 for each O and +7 for Cl
+5. In oxyacids, oxygen has an oxidation state of -2 and hydrogen an oxidation state of +1. Therefore, the single chlorine atom must have an oxidation state of +5 for the total oxidation states to add to zero.+5. In oxyacids, oxygen has an oxidation state of -2 and hydrogen an oxidation state of +1
Hydrogen has an oxidation state of +1 whenever it interacts with a more electronegative element to form a compound (NH3) or whenever it forms an ionic-bonded acid (HClO4) or functions as a cation (NaHCO3). Hydrogen has an oxidation state of 0 in its elemental form. (H2) Hydrogen has an oxidation state of -1 whenever it forms and ionic salt as an anion. (LiH).
Each Br atom has an oxidation number of zero.
No. The oxidation numbers of nitrogen and oxygen do not change.
In chemistry, the oxidation state is a number assigned to an element as an indicator of the degree of oxidation of an atom in a chemical compound."The charge an element would have if it were an ion "Oxidation state is the same as the oxidation number. It is an indicator of the degree of oxidation of an atom in a chemical compound.
In per chloric acid HClO4, the oxidation number of chlorine is +7.
HClO4 (the four is a subscript)
+1 for H, -2 for each O and +7 for Cl
By charge, I assume you mean oxidation number. Oxygen's oxidation number is a very dependable -2, with only a few strange exceptions. A better question would be "What is chlorine's oxidation number in ClO4-?" The answer would be +7.
+5. In oxyacids, oxygen has an oxidation state of -2 and hydrogen an oxidation state of +1. Therefore, the single chlorine atom must have an oxidation state of +5 for the total oxidation states to add to zero.+5. In oxyacids, oxygen has an oxidation state of -2 and hydrogen an oxidation state of +1
It depends on the compound its in. (the range for its oxidation number ranges from -1 to +7 [odd numbers in between are its oxidation numbers exp: -1, +1, +3, +5, +7]) For example if its cl- (only a chlorine ion) then its oxidation number is -1 (simmilar to its valency). If its in the compound NaCl, We know that its total oxidation is 0. (all compunds have an oxidation number of zero) Na has an oxidation number +1. Therefore +1 + x = 0 -> through this you can find the oxidation number of chlorine in this compund. (x representing the oxidation number of chlorine). In this case the answer is x=-1. In the compound HClO4 (perchloric acid), the oxidation number of the total compund is equal to 0. Oxygen has an oxidation number of -2, and hydrogen has an oxidation number of +1. Therefore, (+1) + x + (-2*4) = 0 (oxygen in this compund has 4 atoms so -2 multiplied by 4) Thus: +1 + x + (-8) = 0 +1 + x = 8 x= 8 -1 x= +7 So we can see here that the oxidation number of chlorine has become +7. Do the same for any compound that chlorine is involed in. Hope it helps.
oxidation number of I is -1. oxidation number of F is +1.
Oxidation numbers up to +7 is possible. For example: +7 for Cl in HClO4 or Cl2O7. +6 for S in SO3 or H2SO4 +5 for N in HNO3 or N2O5 +4 for C in CO2
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
NaClO4 + HCl → NaCl + HClO4
Zn has oxidation number +2; S has oxidation number -2
The oxidation number for H is +1, and the oxidation number for O is -1.