0
+1 for each Na
-1 for oxygen (as it is peroxide)
Wiki User
∙ 11y ago
Wiki User
∙ 9y agoSodium's oxidation number is +1.Nitrogens oxidation number is +3. Oxygen's oxidation number is -2.
Wiki User
∙ 6y agoThe oxidation number for Na in Na2O2 is 1+. Recall that in peroxides, O has an oxidation number of 1-, not 2-.
Wiki User
∙ 12y agoNa +1 O-2
Add your answer:
Earn +20 pts
What is the oxidation state of NA in NA2O2 and K in KO2?
The principal oxidation state of NA in NA2O2 and K in KO2 is +1
What is the oxidation number of Na2O2?
+1 for each Na -1 for each O (peroxide)
What type of reaction occurs between Na plus O2?
4 Na + O2 → 2 Na2O2 Na + O2 → Na2O2
What is the oxidation number of na of ci?
The oxidation number of Sodium in the Na + ion = 1
What is the oxidation number of each element in NaCl?
The oxidation number of Na in NaCl is +1, while the oxidation number of Cl in NaCl is -1.
What is the oxidation state of NA in NA2O2 and K in KO2?
The principal oxidation state of NA in NA2O2 and K in KO2 is +1
What is the oxidation number of Na2O2?
+1 for each Na -1 for each O (peroxide)
What type of reaction occurs between Na plus O2?
4 Na + O2 → 2 Na2O2 Na + O2 → Na2O2
What is the oxidation number of na of ci?
The oxidation number of Sodium in the Na + ion = 1
What is chemical symbol for sodium peroxide?
Na2O2, or Na-O-O-Na.
What is the oxidation number of each element in NaCl?
The oxidation number of Na in NaCl is +1, while the oxidation number of Cl in NaCl is -1.
What is oxidation number for Na in NaOH?
The oxidation number is +1. (Oxidation number for an ion is the ionic charge)
What is the oxidization state of oxygen?
The oxidation number of any free element is 0. So if it is oxygen by itself (e.g., O2) then the oxidation number/state is 0. In its compounds the oxidation number of oxygen is -2. This rule only stands if it isn't a peroxide such as H2O2 or Na2O2, in peroxide cases, the oxygen is -1.
What is the Oxidation number of Na Br?
+1 for Na -1 for Br
What is the percent yield for the reaction of 6.92 g of K and 4.28 g of O2 if 7.36 g of KO2 is recovered in the laboratory?
First you need to find the theoretical yield for the reaction:2Na + O2 ---> Na2O2(1) find the theoretical yield of 3.74 g of Na, i.e. if all of the Na is reacted3.74 g Na *(1 mol Na/22.99 g Na)*(1 mol Na2O2 formed/2 mol Na reacted)*(77.98 g Na2O2/1 mol Na2O2) = 6.34 g Na2O2(2) % yield = (actual yield / theoretical yield)*(100%)% yield = (5.34 g / 6.34 g) *(100%) = 84.2% yield
What is the oxidation state of na2so4?
This is a neutral compound. Na shows the +1 OXIDATION NUMBER.
What is the oxidation number of solid sodium carbonate?
Na2C03 Oxidation number of Na = + 1 Oxidation number of O=-2, Oxidation number of C=2x1+x+3(-2)=0 so x=4
