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HCOOH is a weak acid. This in a solution will partially dissociate into its respective ions.
pH = -log(H+)
pH = -log(0.2)
Put above number in your calculator to get your answer.
Wiki User
∙ 15y ago
Wiki User
∙ 10y agoThe substance that you have given (HC2H3O2) is called acetic acid or ethanoic acid and is commonly known as vinegar. Acetic acid is a weak acid and does not ionise completely in solution to produce hydrogen/hydronium ions. To calculate the pH, we need to know the concentration of hydrogen/hydronium ions that is produced by the acid. However, the concentration of the hydrogen/hydronium ion cannot be calculated because the degree of ionisation is not given. The degree of ionisation is a value expressed in percentage form denoting the proportion of the acid that has become ionised. Nonetheless, if we assumed that the acetic acid is completely ionised, we can calculate the pH to be 2 as shown below.
pH = -log10[H+] = -log10[0.01] = 2
Wiki User
∙ 11y agoIt will dissociate to NH4+ and C2H3O2-
both are a weak acid(NH4) and weak base(C2H3O2)
so Ka of NH4 is ~ to the Kb of acetate(C2H3O2) anion
so overall the pH value wouldclose to7.00or Neutral
peanutbutterjelly
This chemical compound is called acetic acid. Being an acid, it will have a pH below 7 for sure!
pH will depend on the concentration of the acid. You can determine the pH using Universal Indicator.
Hope this helps you (:
Wiki User
∙ 14y agoI believe the pH of H2SO3 (or sulfurous acid) is 1.5.
Wiki User
∙ 11y agoIt depends on its concentration in water
Wiki User
∙ 15y ago3.00
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How do you neutralize HC2H3O2 plus LiOH?
Use equimolar quantities: LiOH + HC2H3O2 (acetic acid) --> C2H3O2- (acetate) + Li+ + H2O
How many equivalent OH-1 are there in HC2H3O2?
5
Is vinegar a base in water?
The active ingredient in vinegar is acetic acid (HC2H3O2), which is a weak acid.
Why does HC2H3O2 form ions when it is dissolved in H2O but not when it is in pure form?
Eat some bacon then come back
What is the Lewis Dot Structure of HC2H3O2?
O que significa essa formula
In aqueous solution what pair of compounds in equimolar concentration best represents a buffer system for control of pH?
Hc2H3O2 and NaC2H2O2 or HCL and NaOH or HNO3and NaNO3 or KCL and NaOH?
1.26 x 10-4 mol of HC2H3O2?
This question is quite ambiguous. If you are trying to find pH, then you cannot since Acetic Acid is a weak acid. Weak acids do not dissociate completely and, therefore, have a varying pH level depending on how well it dissociates.
Name of hc2h3o2?
Acetic acid
HC2H3O2 is an electrolyte?
It is a weak electrolyte.
What is the gas evolved when magnesium react with HC2H3O2?
HC2H3O2 is acetic acid. Magnesium will react with water or acids to produce hydrogen gas.
How do you neutralize HC2H3O2 plus LiOH?
Use equimolar quantities: LiOH + HC2H3O2 (acetic acid) --> C2H3O2- (acetate) + Li+ + H2O
What is dose hc2h3o2 stand for?
Acetic Acid
What is the pH of 0.2 M acetic acid ka equals 1.8 x 10-5?
What is the pH of 0.2 M acetic acid Ka equals 1.8 x 10-5? This is an equilibrium problem.When HC2H3O dissolved in water, it forms H3O+1 ions and C2H3O2-1 ions. As the H3O+1 ions and C2H3O2-1 ions bounce around in the water, they reform water and HC2H3O2 molecules.#1 HC2H3O2 + H2O = H3O+1 + C2H3O2-1Ka is the dissociation constant. The dissociation constant is a measure of the number of number of H3O+1 and C2H3O2-1 ions per liter of solution compared to the original number of HC2H3O2 molecules per liter of solution. The brackets [ ] mean moles/liter, which is a measure of the concentration of the substance inside the brackets..#2 Ka = [H3O+1] * [C2H3O2-1] ÷ [HC2H3O2], is the dissociation constant equation.When one molecule of HC2H3O2 dissociates, in water, it forms one H3O+1 ion and one C2H3O2-1 ion.A 0.2 molar solution of HC2H3O2 means 0.2 moles of HC2H3O2 was dissolved in enough water to make one liter of solution#1 HC2H3O2 + H2O = H3O+1 + C2H3O2-1#2 Ka = ( [H3O+1] * [C2H3O2-1] ) ÷ [HC2H3O2]We do not include the concentration of water, because the number of water molecules that do not dissociate greatly exceeds the number that do dissociate. We know this because the Ka is very small.Since we do not know how many HC2H3O2 dissociated, let x equal the moles/per liter of HC2H3O that dissociated forming x moles/per liter of H3O+1 ions and x moles/per liter of C2H3O2-1 ions. Now, substitute x for the [H3O+1] and. [C2H3O2-1].#3 Ka = x * x ÷ [HC2H3O2]#4 Ka = x^2 ÷ [HC2H3O2]#5 x^2 = Ka ÷ [HC2H3O2]#6 x = ( Ka ÷ [HC2H3O2] ) ^0.5Now, substitute Ka = 1.8 x 10-5 for the dissociation, and 0.2 for [HC2H3O2].Solve for the value of x.(You can substitute these values of Ka and [HC2H3O2] into equation #3 and solve for x. I just wanted to show you how to derive the equation.)This answer will be very small, around n x 10^-3.x = [H3O+1] = about 10^-3.pH = - log of the [H3O+1]pH = - log xDon't forget the negative sign.This answer will be between +2 and +3In case you do not know how to do pH problems, I will do an example.What is the pH of 0.1 molar solution of HOBr? (Ka = 2.0 x 10^-9Eq.#1 HOBr + H2O = H3O+1 + Br-1Eq.#2 Ka = ( [H3O+1] * [Br-1] ) ÷ [HBr]Eq.#3 Ka = x * x ÷ [HBr]Eq.#4 Ka = x^2 ÷ [HBr]Eq.#5 x^2 = Ka ÷ [HBr]Now, substitute Ka = 2.0 x 10^-9 for the dissociation, and 0.1 for [HBr].(10^-1)Solve for the value of x.Eq.#5 x^2 = (2.0 x 10^-9) ÷ (10^-1)Dividing powers, means subtracting exponents!! (-9) - (-1) = -8Eq.#5 x^2 = (2.0 x 10^-8)Remember, when you take (n * 10^-8)^0.5 = n^0.5 * (10 ^-8)^0.5Remember, when you take the square root of 10^-8, you get 10^-4, because 10^-4 * 10^-4 = 10^-8Eq.#6 x = (2.0 x 10^-8) ^0.5=x = [H3O+1] = 1.414 * 10^-4pH = - log of the [H3O+1]log 10^x = exponent of 10 = xLog of ( n * 10^-b) = (log n) + (-b)pH = - log (1.414 * 10^-4 )pH = (- log 1.414 + -log * 10^-4 ) = (-0.15) + (+4) = +3.85Don't forget 2 negatives = a positive +4This answer will be between +3 and +4
How many valence electrons does HC2H3O2 have?
5 or 15
How many equivalent OH-1 are there in HC2H3O2?
5
How many moles are there in 500.0g of HC2H3O2 -?
8.32 MOLES
How many number of carbon atoms are present in 0.062 mol acetic acid HC2H3O2?
The number of carbon atoms which are present in 0,062 mol acetic acid HC2H3O2 is 0,747.10e23.
