What is the concentration of OH ions in a HCl solution whose hydrogen ion concentration is 2.7M?

Answer 1

1.0 * 10-4 is the OH- concentration

[H30+] = 10(-pH) = 10-10 = 1.0 * 10-10 M

[OH-] = (Kw) / [H30+] = (1.0 * 10-14) /(1.0 * 10-10) = 1.0 * 10-4 M

Shortcut:

The pH and pOH values must add up to equal pKw, which value is 14.0 (at 25o).

Given the pH of 10, you simply subtract 10 from the required 14 to get -4. Insert the -4 into the concentration format (1.0*10x) to get 1.0*10-4

Answer 2

pOH = - log([OH-]) together with pH + pOH = 14*) in which [X] = concentration of X (in mol/L), it's possible to calculate the pH.

[X] = [OH] = 10 mol/L

pOH = -log(10) = -1.0

pH = 14 - (-1.0) = 15.0

*) Only valid at 25oC.

Answer 3

Assuming the disassociation constant (K w)of water being 9.55 * 10 -14 at a certain temperature K w = [OH-] * [H3O+] [H3O+] =4.775 * 10 -10 M

Answer 4

I'm pretty sure it's 1x 10 -2M because it must equel 14 that is the highest it can go the total pH

Answer 5

To find the pH use this:

-log(2 X 10^-14 M)

= 13. 7 pH ( you could call it 14 )

Answer 6

If the pH = 4, then [H+] = 1x10^-4 M and since [H+][OH-] = 1x10^-14, the [OH-] = 1x10^-10M.

Answer 7

pH=2.0 (pOH = 12.0 = 14-pH )

Answer 8

fyl

Answer 9

12