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Using Pythagoras:

side_length² + side_length² = diagonal²

→ 2 × side_length² = (3√2)²

→ 2 × side_length² = 3³ × 2

→ side_length² = 3²

→ side_length = 3

→ perimeter = 4 × side_length = 4 × 3 = 12 units.

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Q: What is the perimeter of a square whose diagonal is 3 square root of 2?
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