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pH = pKa + log([A-]/[HA])

pH = pKa+log([conjugate base]/[undissociated acid])

The actual meaning of pKa: the negative log of the dissociation constant, which is a measure of strength of an acid/base

when pKa = pH, there is equal concentration of acid and its conjugate base. pKa helps to understand the nature of acid and base like pH:

pKa 2 but 7 but < 10 -- weak base pKa >10 --strong base

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14y ago
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12y ago

pH is a measure of the concentration of hydronium ions in solution. pKa is a measure of how much an acid wants to dissociate in a solution.

pH has almost no effect on how much a strong acid dissociates. A strong acid added to a mixture drives the pH down by 1 for every 10 times the strong acid concentration goes up (because pH is a log scale--every unit on a log scale represents another power of 10). pH does however have an impact on how much a weak acid dissociates. Of course the pH drops when an acid does dissociate, and weak acids dissociate some, so they are interrelated. An equilibrium is reached. pKa tells you where that equilibrium will be reached and what the final pH will be:

pH = pKa + log([A-]/[HA])

Notice that the only time pH = pKa is when the acid is exactly half dissociated; when [A-] = [HA]. That is the exact point that you want buffer solutions to be. But that's another story.

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11y ago

For buffer solutions the pH and pKa functions are correlated by the following relationship:

pH=pKa+Log([A-]/[HA], in which the second term is defined as conjugated acid [A-] over undissociated acid [HA].

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14y ago

In general , the Henderson- Hasselbach equation is given by:

pH= pKa + log [base]/ [acid]

since the ratio is 1 to 1 : pH = pKa + log 1 , log 1= 0

pH = pKa when the ratio is 1 to 1

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14y ago

one is the concentration of H+, the other is the constant that dictate the ability of a substance to release proton to water

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12y ago

look up relationship of pKa to pH. (Hasselbach equation). Then convert pKb to pKa by the following relationship: 14-pKb=pKa

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6y ago

A simple relation is: pOH = 14 - pH

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Q: What is the relation between pH and pOH?
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