answersLogoWhite

0


Best Answer

Four 4 ohm resistors in parallel have an equivalent resistance of 1 ohm.

Two resistors R1 and R2 in parallel have an equivalant resistance of R1R2/(R1+R2). Plug in 4 ohms for two of the resistors and you get 2 ohms. Repeat and you get 1 ohm.

User Avatar

Wiki User

14y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

11y ago

1/R = 1/R1 + 1/R2

So in this case: 1/R = 1/2 + 1/3 = 3/6 + 2/6 = 5/6

That is: R = 6/5 = 1.2 ohm

This answer is:
User Avatar

User Avatar

Wiki User

11y ago

Pair implies two, but the question asks about four. In any event, the total resistance in a series circuit is the sum of the individual resistances.

This answer is:
User Avatar

User Avatar

Wiki User

11y ago

Ask your father

This answer is:
User Avatar

User Avatar

Wiki User

6y ago

4 ohms.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the equivalent resistance of a pair of 4 ohms resistor in parallel?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Physics

Three 8.0-W resistors are connected in series What is their equivalent resistance?

Three 8.0-W resistors are connected in parallel. What is their equivalent resistance?


Is resistor measured in amps?

No, a resistor isn't measured at all. A resistor has a quality called "resistance" - and that value is measured. Resistance is measured in Ohms.


What is the equivalent resistance through the entire circuit?

The equivalent resistance is the overall effect all of the resistances in a circuit has. Put another way, it is the value a single resistor in a circuit would have to be in order to have the same effect as all of the resistors resistors combined in a given circuit.


What is the equivalent resistance of a parallel circuit with a 5.0 kΩ resistor a 2.5 kΩ resistor and 10.0 kΩ resistor?

Just use the formula for parallel resistors: 1/R = 1/R1 + 1/R2 + 1/R3 + ... In this case, replace R1 with 5, R2 with 2.5, R3 with 10, and solve for "R".


How do you create a circuit which has a 13.75 Ohm resistance using only 1Ohm resistor?

If you're sure that every resistor is exactly 10 ohms, and you need exactly13.75 ohms, then you can do it this way:-- Connect four resistors in parallel. Effective resistance of the combination = 2.5 ohms.-- Connect eight resistors in parallel. Effective resistance of the combination = 1.25 ohms.-- Connect in series: the 4-resistor unit, the 8-resistor unit, and a single 10-ohm resistor.Effective resistance of the combination = (2.5 + 1.25 + 10) = 13.75 ohms.In the real world, however, the combination of (2.5 + 10) = 12.5 would be closeenough to work. And actually, a single 10-ohm resistor might be close enough.Or you could just connect a single 10-ohm resistor to the ohm-meter, take afingernail file, file a small notch in the side of the resistor while watching themeter, stop filing when the resistance arrives at 13.4 ohms, see what it is whenit cools from all the filing and settles down, then make small additional scrapesuntil you have your 13.75 ohms. This might be just as fast as the 23 solder-joints required for the procedure described above, and you save 12 resistors !So what could be bad ! ?

Related questions

A resistor of 10k ohms resistance with tolerance of 5 percent is connected in parallel with another resistor of 5k ohms resistance and 10 percent tolerance.what is tolerance limit of parallel network?

6.67%


What resistance must be connected in parallel to 6.0-ohm resistor to reduce the combined resistance to 15-ohm?

No such resistor exists. Any resistor placed in parallel with a 6.0 ohm resistor is going to reduce the combined resistance below 6.0 ohms.


How do you place 3 resistance to get the total resistance of 1 ohm?

It depends on the resistance of each resistor. If each resistor, for example, is 0.333 ohm, then you could connect them in series. If each resistor, for example, is 3 ohms, then you could connect them in parallel.


When 2 resistors are connected in parallel r1r2 are?

Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.


What is the equivalent resistance of three resistor with 3 ohms connected in star?

There is no 'equivalent resistance' for three resistors connected in star.


What is the relation between the total resistance of a parallel connection network of resistors in reference to their single resistance?

The equivalent total resistance of resistors connected in parallel is lower than the resistance of the smallest resistor. The general formula for calculating the total resistance of n resistors in parallel is Rt = 1 / (1/R1 + 1/R2 + ... 1/Rn) For two resistors in parallel, the formula simplifies to Rt = (R1 x R2) / (R1 + R2) If R1 = 10K ohms and R2 = 4.2K ohms, the total resistance of R1 in parallel with R2 is (10,000 x 4,200) / (10,000 + 4,200) = 2957.7 ohms. The total resistance is less than the smallest resistor (4.2K). For three resistors in parallel, the formula is Rt = 1 / (1/R1 + 1/R2 + 1/R3) If R1 = 100 ohms, R2 = 68 ohms, R3 = 1K ohm, the total resistance of these three resistors connected in parallel is: Rt = 1 / (1/100 + 1/68 + 1/1000) = 38.9 ohms The total resistance (38.9 ohms) is lower than the smallest resistor (68 ohms).


Two identical resistors are connected in parallel and then wired in series to a 40-ohm's resistor If the total equivalent resistance is 55-ohm's. What is the value of R?

30 ohms.


Why are resistances parallel to short circuits neglected in a circuit?

You can consider a short circuit to be a resistor with R=0 Ohms. It is then clear by the equation for calculation of parallel resistance that the combined resistance of a resistor in parallel to a short circuit is 0. Consider the following example with R1= 1k Ohms and R2= 0 Ohms: Rtotal = R1*R2 / (R1+R2) = R1*0 / R1 = 0 Ohms.


What is the total resistance of a circuit with a 75 ohm and a 150 ohm resistister in parallel?

The equivalent resistance of 75 ohms and 150 ohms in parallel is(75 x 150)/(75 + 150) = 50 ohms


Three 8.0-W resistors are connected in series What is their equivalent resistance?

Three 8.0-W resistors are connected in parallel. What is their equivalent resistance?


What is the total resistance of a 6-ohm resistor and a 12-ohm resistor in a parallel series?

In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms


Given 4 resistors each have equivalent resistance of 100 ohms show how these resistors might be combined to produce an equivalent resistance of a 40 ohms b 250 ohms c 100 ohms?

a) Put 2 of the resistors in series to make a 200 ohm resistor. Then put the 100, 100, and 200 ohm resistors in parallel for 40 ohms. b) Put 2 resistors in parallel for 50 ohms. Put the 50, 100, and 100 ohm resistors in series for 250 ohms. c) Put 2 resistors in parallel for 50 ohms. Repeat with other 2 resistors. Put the two 50 ohm resistors in series for 100 ohms. This configuration can withstand 4 times the wattage of each individual resistor.