· 1 J/(kg K) = 2.389x10-4 kcal/(kg oC) = 2.389x10-4 Btu/(lbm oF) · 1 kJ/(kg K) = 0.2389 kcal/(kg oC) = 0.2389 Btu/(lbm oF) · 1 Btu/(lbm oF) = 4,186.8 J/ (kg K) = 1 kcal/(kg oC) · 1 kcal/(kg oC) = 4,186.8 J/ (kg K) = 1 Btu/(lbm oF) Metal Specific Heat Capacity - cp (kJ/kg K)(kcal/kgoC) (Btu/lbmoF) Lead 0.13 0.031 0.03 · 1 J/(kg K) = 2.389x10-4 kcal/(kg oC) = 2.389x10-4 Btu/(lbm oF) · 1 kJ/(kg K) = 0.2389 kcal/(kg oC) = 0.2389 Btu/(lbm oF) · 1 Btu/(lbm oF) = 4,186.8 J/ (kg K) = 1 kcal/(kg oC) · 1 kcal/(kg oC) = 4,186.8 J/ (kg K) = 1 Btu/(lbm oF) Metal Specific Heat Capacity - cp (kJ/kg K)(kcal/kgoC) (Btu/lbmoF) Lead 0.13 0.031 0.03
According to scientists, the specific heat capacity of gold is observed at 0.129 in Joules per gram per degrees Celsius.
The specific heat capacity of lead is 0.160 at 25oC in J/go
25 °Celsius
128 J/kg°C
Water has much higher specific heat than lead. All metals have fairly low specific heat values.
The specific heat of lead is 0.0305 K cal/kg deg C. The heat absorbed will be 38x(180-26)x0.0305 = 178.5 Kcal = 746.1 K joules
specific heat(; your welcome!
heat capacity= specific heat x mass molar heat capacity = specific heat x molar mass - Hope this helps!!
Water has a specific heat of 4.18J/gC, so set up the specific heat equation: C (spec. heat)=q (joules)/mass x temp. change, so: 4.18 (spec. heat of water) = q/46g(100deg), so q = 4.18(4,600) = 19,228 joules (or 19.228 kJ).
The unit for specific heat is Joules/g-Kelvin or it can be Joules/g-Celsius J= Joules g= Grams C= Celsius
Joule/kilogram-kelvin The SI unit is joules / kelvin. This is valid for an object of any size, but if you want the typical specific heat for a certain type of material, you have to standardize it, resulting in either joules / (kelvin x kilogram) or joules / (kelvin x mole).
it is in joules. 03o
it is in joules. 03o
Specific heat of lead = 0.160 J/gC 45 pounds (454 grams/ 1 pound) = 20430 grams Use. q(Joules) = mass * specific heat * change in temp. q = (20430 grams)(0.160 J/gC)(100 C - 62 C) = 1.2 X 10^5 Joules ------------------------- or ------------------------- 1.2 X 10^5 Joules (1 calorie/4.184 Joules) = 29688 calories
In SI, specific heat capacity is measured in joules per kilogram kelvin.
539 joules, approx.
I need to make some conversions for my own convenience. 750 calories (4.184 Joules/1 calorie) = 3138 Joules ----------------------- Lead specific heat (c) = 0.160 J/gC Now, q = mass * specific heat * change in temperature 3138 Joules = (250 g Pb)(0.160 J/gC)(Tf - 28.0 C) 3138 J = 40Tf- 1120 4258 = 40Tf 106 Celsius = Final temperature of lead ----------------------------------------------------
Specific heat is the heat required to raise the temperature of a unit mass by one degree. It is measured by joules.
Water has much higher specific heat than lead. All metals have fairly low specific heat values.
The Specific Heat Capacity of water is 4,184 Joules per kg per Kelvin
The unit of specific heat is Joules per gram per degree (C) or Joules per gram per degree (K). It comes from Q (heat) per mass per change in temperature (T) or Specific heat = Heat (Q)/ Mass(M) . Change in Temperature (Delta T).