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1 mol Na2SO4 will dissociate to 2 mol Na+ and 1 mol SO42- Therefore 0.350 M Na2SO4 will dissociate to 0.350*2 = 0.700 mol Na+ and 0.350*1 = 0.350 mol SO42- Therefore the total concentration of ions is 0.700 mol + 0.350 mol = 1.050 mol.

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Q: What is the total molar concentration of ions in a 0.350 M solution of the strong electrolyte Na2SO4 assuming complete dissociation?
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