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We need to convert miles per hour into meters per second as this formula,

KE = 1/2mV^2, needs to use meters per second.

40 mph (1609 meters/ 1 mile)(1 hour/3600 sec.)

= 17.877 meters per sec.

KE = (1500 kg)(17.877 m/s)^2

= 4.8 X 10^5 Joules of kinetic energy

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13y ago
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10y ago

3000lbs = 1361 kg

60 mph = 26.8 meters/s

kinetic energy = 1/2m*v^2

680.5 * 26.8^2

680.5* 718.2 = 488,735.1 joules

==========================

Alternative presentation:

KE = 1/2 (M) (V)2 =

0.5 x (3,000 lbs x kg/2.20462 lbs) x (60 mi/hr x 1,609.344 m/mi x hr/3,600 sec)2 =

489,500.1 joules (rounded)

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13y ago

KE = 1/2mV^2

300 Joules = 1/2(1500 kg)V^2

multiply through by 2

600 = (1500)V^2

divide both sides by 1500

0.4 = V^2

take square (positive) root of both sides

Velocity = 0.632 m/s

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14y ago

We have to ignore friction and air resistance, because the question doesn't include any data for them, and they would make the problem too complicated. We'll just consider the nice simple case where we have a 1500-kg object out in the middle of nowhere, which we want to accelerate with the application of a single force, and the figure of 3 m/s2 is involved in the problem somehow. There is a thorny semantic issue here, which will be hard to explain but I'll try: The wording of the question is somewhat confusing. Do you want to accelerate the car to a speed of 3 m/s ? Or do you want it to accelerate at the rate of 3m/s2 ? If you simply want to push the car until its speed is 3 m/s, then any force will do the job. Any force will accelerate the mass. It's just that a greater force will get you to the target speed sooner, and a smaller force will take longer. That's true even if we don't know the mass of the car. Now, if you want the car to accelerateat the rate of 3 m/s2, now we have a nice little physics problem. I think this is what you intended. Force = (mass) times (acceleration) Force = (1,500 kg) times (3 m/s2) = (1,500 x 3) (kg-m/sec2) = 4,500 Newtons

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10y ago

Before we get started ... in case I forget it later, I just want to mention that

"45 mph" is only a speed, not a 'velocity'.

Kinetic energy = 1/2 (mass) x (speed)2

That formula is pretty simple, but in order to just plug the numbers in into it, they

have to be the mass and speed in SI (metric) units. So we'll calculate those first.

-- Assuming that the car is driving on or near the surface of the Earth, its weight

of 3,000 pounds tells us that its mass is 1,360.779 kilograms. (rounded)

-- 45 miles per hour is equivalent to 20.117 meters/second. (rounded)

KE = (1/2) (mass) (speed)2 = 275,344 joules(rounded)

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11y ago

Kinetic Energy is (1/2)mv2, so in this case it is (1/2)(1,500)(20)2, or 300,000 Joules.

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3y ago

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Q: What is the kinetic energy of 3000 lb car traveling at 60 mph?
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