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What is the volume in liters of 10 0 moles of nitrogen gas at 200 kelvin and 4 5 ATM?
Wiki User
∙ 11y ago
Using the ideal gas law: PV = nRT, and R = 0.08206 L·atm·mol-1·K-1 (see related link), we have:
Assuming you meant 10.0 moles and 4.5 atmospheres: (4.5 atm)*(V) = (10.0 mol)*(0.08206 L·atm·mol-1·K-1)*(200 K ), Solving for V is 3.6471 liters
Wiki User
∙ 11y ago
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