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Resistance R =p(L /A)i,e Resistance(R) of a conductor will be directly proportional to its length(L) ==> if the length of the conductor increases its resistance also will increase.i,e Resistance(R) of a conductor is inversely proportional to its cross section area(A) ==> if the Area of the conductor increases its resistance also will decrease.
Resistance R =p(L /A)i,e Resistance(R) of a conductor will be directly proportional to its length(L) ==> if the length of the conductor increases its resistance also will increase.i,e Resistance(R) of a conductor is inversely proportional to its cross section area(A) ==> if the Area of the conductor increases its resistance also will decrease.
No, the resistance is fixed by the cross section and length of the conductor and does not vary with voltage.
Resistance of a conductor is defined by the specific resistivity, area of cross section and the length of the conductor. R = rL/A, where R is resistance in OHMs, r is specific resistance, L length in mm, A is area of cross section in sq mm
Resistance of a conductor is defined by the specific resistivity, area of cross section and the length of the conductor. R = rL/A, where R is resistance in OHMs, r is specific resistance, L length in mm, A is area of cross section in sq mm
Doubling the diameter of a circular-section conductor will quadruple its cross-sectional area and, therefore, reduce its resistance by a quarter. Doubling the length of a conductor will double its resistance. So, in this example, the resistance of the conductor will halve.
The material, the length, the cross section.
Area of cross section: Resistance R is inversely proportional to the area of cross section ( A) of the conductor. This means R will decrease with increase in the area of conductor and vice versa. More area of conductor facilitates the flow of electric current through more area and thus decreases the resistance. This is the cause that thick copper wire creates less resistance to the electric current.
For conductor the resistance (R) is directly proportional to the length (L) of the conductor, and the area of cross-section (A). When you stretch the conductor to increase its length, its area of cross-section will decrease. The decrease in area of cross-section can be found in the following way: The volume of the cylinder will remain same. The initial volume of the cylinder is = A Х L Suppose, the area of cross-section becomes A/ and the resistance becomes R/. Hence, the resistance increases 4 times. Hope this helps you, Keep posting and have a nice day!
Low resistance.AnswerSince resistance is inversely proportional to the cross-sectional area of a conductor, increasing the diameter ('thickness') of a conductor will reduce its resistance.For example, doubling the diameter of a circular-section conductor will quadruple its cross-sectional area, and reduce its resistance by one quarter.
It can be because of the material used.As we know R=PL/A where R=resistance P=resistivity of the material used L=length of the conductor A=area of cross section of the conductor
The factors are: length, cross-sectional area and nature of substance.