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This is kind of non-specific, but I'm assuming you're looking for the values of x that will make the following true:
x3-2x2-8x = 0
To find these values of x, you must factor the polynomial expression to the left of the equal sign.
x3-2x2-8x = x(x2-2x-8) = x(x-4)(x+2) = 0
By the zero identity, setting each individual factor equal to zero will yield a valid solution to the original equation:
x = 0
x-4 = 0, x = 4
x+2 = 0, x = -2
So the following values of x will solve the equation:
x = 0
x = 4
x = -2
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∙ 13y ago
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