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We would object to that statement, and argue that the motion of a projectile after launch is determined by the speed and direction of the launch.
The two main factors that affect the range of a simple projectile are the angle and speed of the launch. Both of these can be included in the launch velocity, which is a vector that is usually split up into vertical and horizontal components for processing.There are other factors, like wind resistance (including spin/swing) and changes in gravity, but these are fairly insignificant unless you need high precision or are dealing with projectile motion on a large scale or with objects that aren't dense.
It depends on the angle and speed at which it is fired.
Assuming the angle is the angle the initial trajectory makes with the ground, that it's launched with the same speed in both cases, that it's launched from an initial height of zero, that it stops dead as soon as it touches the ground and doesn't bounce or roll, and that we can neglect air resistance (sorry for all that detail, but it does matter)... Both projectiles will end up with the same net displacement, though the 60 degree projectile will have taken a longer path to get there.
If the projectile's velocity has a horizontal component - in other words, it doesn't go straight up - then its speed will never be zero.
We would object to that statement, and argue that the motion of a projectile after launch is determined by the speed and direction of the launch.
The two main factors that affect the range of a simple projectile are the angle and speed of the launch. Both of these can be included in the launch velocity, which is a vector that is usually split up into vertical and horizontal components for processing.There are other factors, like wind resistance (including spin/swing) and changes in gravity, but these are fairly insignificant unless you need high precision or are dealing with projectile motion on a large scale or with objects that aren't dense.
In a perfect system, with no air resistance, the arc that a projectile moves through is a parabola. The shape of the parabola is dependent of various parameters including the initial velocity (speed and angle of launch) as well as the prevailing gravity. It could also describe a circle if the launch criteria are just right for the gravity, such as a satellite orbiting the Earth.
It depends on the angle and speed at which it is fired.
Yes. They will both initially be moving at the same speed.
The max height depends only on the angle and speed at release. It doesn't depend on the projectile's weight.
Speed, weight, and shape of the projectile- along with the angle at which the barrel is raised above the horizonatal.
Factors include the angle at which it is fired, the speed of the projectile, its shape (ballistic coefficient) the air pressure and humidity.
Launch angle varies from person to person and is dependent on swing speed and spin rate.
projection speed projection angle projection height
Assuming the angle is the angle the initial trajectory makes with the ground, that it's launched with the same speed in both cases, that it's launched from an initial height of zero, that it stops dead as soon as it touches the ground and doesn't bounce or roll, and that we can neglect air resistance (sorry for all that detail, but it does matter)... Both projectiles will end up with the same net displacement, though the 60 degree projectile will have taken a longer path to get there.
The way to understand projectiles is to treat their speeds as two different speeds. Treat one speed as how fast the projectile moves up or down relative to the ground, and treat the other speed as how fast the object moves left to right. This is called splitting the velocity into components. Each component is independent of the other, meaning that no matter what happens to the x (the horizontal speed) component, the y (the vertical component) will be unaffected. To determine these components, you will need to know how long the object was in the air. Take the total x component and divide it by the time the object is in the air. That is the x component. Then take that and multiply it by the inverse cosine function of whatever angle the projectile was launched at. That will give you the inital velocity of the object. --An AP Physics Student Bored in Study Hall