2NaCl + Pb(NO3)2 ---H2O--> 2Na(NO3) + PbCl2
Double displacement rxn, Na replaces Pb because its higher on the activity series table. The product is NaNO3 which is dispersed through the solvent as free ions and PbCl2 is the precipitate because it is insoluble.
Strontium sulfate. You have 4 ions here... Two cations: H+ and Sr2+ Two anions: NO3- and SO42- To form an insoluble compound, you need to create a REALLY stable ionic compound, which means hooking together some combination of cation and anion that is stable enough together that they would not want to be apart and interacting with lots of polar water molecules. So let's look at the possibilities: HNO3 -- Can't possibly be insoluble for two reasons: (1) HNO3 is a covalent compound out of water---a gas at room temperature, not a solid. You don't get insoluble solids from compounds with hydrogen as a cation because they are not ionic. (2) Nitrate is soluble with EVERYTHING. It is perhaps the most soluble anion out there. So it will never form an insoluble solid. SrSO4 -- So by process of elimination this has to be it. Sulfate compounds are often soluble, but forms insoluble (or partially insoluble) compounds with all of the alkaline earth metals starting with Calcium and going down.
Sulfuric acid reacts with most metals via a single displacement reaction to produce hydrogen gas and the metal sulfate. Dilute H2SO4 attacks iron, aluminium, zinc, manganese, magnesium and nickel, but reactions with tin and copper require the acid to be hot and concentrated. Lead and tungsten, however, are resistant to sulfuric acid. The reaction with iron (shown) is typical for most of these metals, but the reaction with tin is unusual in that it produces sulfur dioxide rather than hydrogen.Fe(s) + H2SO4(aq) → H2(g) + FeSO4(aq)Sn(s) + 2 H2SO4(aq) → SnSO4(aq) + 2 H2O(l) + SO2(g)
So no reaction takes place between lead and Sulfuric acid. The equation would be as follows: Pb (s) + H2SO4 (aq) = Pb (s) + H2SO4 (aq)
:)
Pb(NO3)2 (aq) + H2SO4 (aq)=> PbSO4(s) + 2HNO3 (aq)
Pb2+(aq)+2NO3-(aq)+2H+(aq)+SO4-(aq) => PbSO4(s)+2H+(aq)+2NO3-(aq)
Pb2+(aq)+SO4-(aq)=>PbSO4(s)
Pb2+ + 2 Cl- ↔ PbCl2↓
The precipitation is incomplete and strongly depending on elemental concentrations and solvent temperature.
The reaction is:
Na2CO3 + Pb(NO3)2 = PbCO3 + 2NaNO3
The lead carbonate is a white precipitate.
lead nitrate + copper sulphate --> lead sulphate + copper nitrate
Pb(NO3)2 + CuSO4 --> PbSO4 + Cu(NO3)2
The molecular equation is Pb(NO3)2 + H2SO4 => PbSO4 + 2 HNO3.
Pb2+(aq) + SO42-(aq) --> PbSO4(s) , because the other salt NaNO3 is soluble.
lead sulfate
whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed. whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed.
Silver chloride will deposit as a white precipitate.
I'd think that it is a chemical change... Mixing NaCl(Sodium Chloride) with AgNo3(Silver Nitrate) in aqueous states is simple precipitation... unless u're talking about mixing the powders by themselves?
You will form a precipitate composed of silver chloride, AgCl, which is insoluble in water.
If the sodium sulfate and barium nitrate are both in solution in water, a precipitate of barium sulfate will be formed, because this salt is much less soluble in water than barium nitrate, sodium sulfate, or sodium nitrate.
Any precipitate is formed.
whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed. whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed.
an example of a precipitate is: silver nitrate + sodium chloride = silver chloride and sodium nitrate the precipitate is the silver chloride it forms a white powder
huG A panda
when sodium chloride and silver nitrate reacts then we get silver chloride and sodium nitrate.
A precipitate is a solid which 'falls down' from the solution. Thus silver chloride is the precipitate.
The reaction is:LNaCl + AgNO3 = AgCl + NaNO3The white precipitate is silver chloride.
The precipitate is magnesium carbonate.
Formation of a precipitate is evidence of a chemical reaction.
A precipitate of yellow Lead iodide and Sodium nitrate are formed
Because the product silver chloride is a white precipitate.
Silver chloride will deposit as a white precipitate.