It is a synthesis reaction because the two substances are combining to form one.
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The element that is oxidized in the reaction 4Al + 3O2 → 2Al2O3 is aluminum (Al). In this reaction, aluminum loses electrons and undergoes oxidation to form aluminum oxide (Al2O3).
The balanced chemical equation for the reaction between Al and O2 is: 4Al + 3O2 -> 2Al2O3 Therefore, the coefficient needed for Al to balance the equation is 4.
When aluminum burns, the reaction is highly exothermic.
Al4C3 +12H2O = 4Al(OH)3 + 3CH4
The aluminium oxide is AlO3.
The element that is oxidized in the reaction 4Al + 3O2 → 2Al2O3 is aluminum (Al). In this reaction, aluminum loses electrons and undergoes oxidation to form aluminum oxide (Al2O3).
This is a synthesis reaction, and when it's balanced, it looks like this: 4Al + 3O2 --> 2Al2O3
The balanced chemical equation for the reaction between Al and O2 is: 4Al + 3O2 -> 2Al2O3 Therefore, the coefficient needed for Al to balance the equation is 4.
4Al + 3O2 -> 2Al2O3
4Al+3O2-->2Al2O3
When aluminum burns, the reaction is highly exothermic.
2Al2O3 + 3C -> 3CO2 + 4Al
Al4C3 +12H2O = 4Al(OH)3 + 3CH4
The aluminium oxide is AlO3.
4Al(s)+3O2(s) - > 2Al2O3(s)
When aluminum carbide reacts with water, the products of the reaction are aluminum hydroxide and methane gas. The balanced equation for this reaction is Al4C3 + 12H2O -->4Al(OH)3 + 3CH4(g)
No. If you mean 4Al3O2. And If you mean 4Al + 3O2 ------> AL2O, it is still not balance.