Start with the balanced equation of the formation of water:
2 H2 + O2 --> 2 H2O
It takes one mole of oxygen to produce 2 moles of water.
32.0 g O2 * (1 mol O2/32.00 g O2) * (2 mol H2O/1 mol O2) * (18.02 g H2O/1 mol H2O) = 36.04 g
Therefore, about 36.04 grams of water will be produced from 32.0 grams of oxygen gas, assuming that it can react with unlimited amounts of hydrogen gas.
To the justified number of significant digits, the masses given correspond to one mole of diatomic oxygen and two moles of diatomic hydrogen. The formula of water is H2O; therefore, these numbers of moles produce two moles of water molecules, and the number of the latter is twice Avogadro's number = 1.2 X 1024.
32g of oxygen is 2 moles oxygen (O) atoms. To make this react completely you require 4 moles of hydrogen (H) atoms which weighs 4g.
Added:
Not by atoms but by molecules, like the balanced equation will give:
O2 + 2H2 --> 2H2O
Reactant [O2:H2] molecular ratio = reactant molar ratio = 1 : 2
O2 = 32 g O2 = 32g / (2*16.0) g/mol O2 = 1.0 mol O2
2H2 = 2.0 mol H2 = 2.0 * (2*1.008) g/mol H2 = 4.03 = 4.0 g H2
8 grams
4
Hujj
Two moles of water are produced.
67.5 grams of H2O
7.8 grams
no H2O molecules are produced:)
The answer is 0,44 moles.
Two moles of water are produced.
67.5 grams of H2O
If all of th 120 g of glucose are converted to energy, how many grams of h2o and co2 will be produced?
Balanced equation first. 2H2 + O2 -> 2H2O 250 moles O2 (2 mole H2O/1 mole O2) = 500 mole H2O produced now, since I am forgetful, I will use density formula at 25 C Density = grams/milliliters 500 moles H2O (18.016 grams/1 mole H2O) = 9008 grams H2O 0.9982 g/ml = 9008 grams/milliliters 9024.24 milliliters H2O this is...... 9.02 liters of water produced in this reaction.
18 grams
7.8 grams
The mass of nitrous oxide is 262,8 g.
no H2O molecules are produced:)
Hello
Let me help you a little: water is H2O
Approx 18 grams.
The answer is 0,44 moles.