There would be nine 3s with a remainder of two. 3 goes into 27 nine times, so the remaining two (29-27) are left over.
5/1
5 r 1
9 r2
how many 3s gointoo 33
103
29 does not divide evenly into 95, but it will go into 95 3 times. 95 / 29 = 3.2758620689655172413793103448276...
29 ways. Note that, since 32 is even, 3s can appear only an even number of ways.
29
There are 29 3s because there also a 3 in the how many 3s are in 83333333333333333333333333333
0
3x7+4x2
18
3 x 30 = 90 3 x 29 = 87
how many 3s gointoo 33
28 3s
103
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
29 does not divide evenly into 95, but it will go into 95 3 times. 95 / 29 = 3.2758620689655172413793103448276...
divide by 100 = 0.29 meters
29 ways. Note that, since 32 is even, 3s can appear only an even number of ways.