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BH3 does not obey octet rule.

it has a total of six electrons only.

boron has three electrons in the valence shell and it accepts one electron from each hydrogen

BH3 is a planar molecule and is found only in the gaseous state.

BH3 dimerises to form B2H6 with 4 terminal hydrogens attached by normal covalent bonds and 2 hydrogen bridges , 3 centre 2 electron bonds. Once again in the dimer it does not obey the octet rule.

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11y ago
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12y ago

In borane (BH3) boron has three valence electrons. Even when bonded to those three hydrogens, it's still two electrons short of the octet.

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Q: Does the Lewis structure of BH3 contain an atom that does not obey the octet rule?
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