Please note that the differences are only slight - so slight that you can round
the acceleration due to gravity to a value of 9.8 m/s2, anywhere on Earth,
with reasonable accuracy. The reasons for the (slight) difference are:
1) The Earth is not a perfect sphere. In different places, you are at a different
distance from the Earth's center.
2) The Earth rotates. This produces an apparent centrifugal force. Stated in
other terms, if you are at the equator, while an object falls towards Earth, the
Earth moves away from it due to the rotation (centripetal acceleration).
Because the acceleration of gravity on the surface of any given body depends on the mass of the body and its radius ... the distance of the surface from the center. Mars' mass ... about 11% of Earth's ... and Mars' radius ... about 53% of Earth's ... combine to produce about 38% of Earth's gravitational acceleration at the surface of Mars.
No, your weight is just the acceleration due to the Earth's gravity,
On the earths surface gravity pulls you down.
9.81 m/s2 gravity is dependant on the total mass of the two bodies, and the distance between their mass centers, and irrespective of any motion or rotation on earth, their would be a very small acceleration due to rotation about the earths axis (0 at the poles , maximum at the equator) , but this is a totally seperate issue
If you have a known rate of acceleration and radius (such as at the earths surface), you can use the following equation to calculate the acceleration at another radius.a = k / ((d / r)^2)key:a = new acceleration rate ((m/s)/s)d = new radius (metres)k = known acceleration rate ((m/s)/s)r = known radius (metres)so if:d = 9 000 000 metresk = 9.82 (m/s)/s (acceleration at earths surface)r = 6 371 000 metres (radius at earths surface)then:a = 4.92 (m/s)/s
The acceleration of gravity at its surface is currently estimated as 0.4 m/s2 .That's about 4% of the acceleration of gravity on the Earth's surface.
The force of gravity on the earth is 9.8 m/s^2
Because the acceleration of gravity on the surface of any given body depends on the mass of the body and its radius ... the distance of the surface from the center. Mars' mass ... about 11% of Earth's ... and Mars' radius ... about 53% of Earth's ... combine to produce about 38% of Earth's gravitational acceleration at the surface of Mars.
earth is 81.3 times the mass of the moon . acceleration due to gravity at earths surface = 9.82 (m/s)/s acceleration due to gravity at moons surface = 1.62 (m/s)/s . 1 kg at earths surface, force = 1 * 9.82 = 9.82 newtons 1 kg at moons surface, force = 1 * 1.62 = 1.62 newtons
No, your weight is just the acceleration due to the Earth's gravity,
Different air pressure, so there is more/less air resistance.
because all are measured at the same radius from the earths cog, if you doubled this distance, the acceleration would be only one quarter that of the surface
on the surfaceNote:Since the earth's composition is not homogeneous, the gravitational acceleration onthe surface is probably less than what it is some small distance below the surface,but it's certainly greater than at the center.
The Sun's gravity, at its surface, is about 28 times Earth's surface gravity.
Earths surface of gravity is 4.6m/s2 more than moons.
Both mercury and mars have a gravity which is around 38% of earths. Mercury's gravity is 37.8% of earths, Mars' gravity is 37.7% of earths.
if you double the earths density say , standing at the surface you would experience twice the acceleration, weight would be doubled