Knowing the slant height helps because it represents the height of the triangle that makes up each lateral face. So, the slant height helps you to find the surface area of each lateral face.
The surface area of a cone: SA = pi*r² + pi*r*s (r is radius, s is slant height) The surface area of a pyramid: SA = [1/2 * Perimeter * Slant Height] + [Base Area]
Surface area of a triangular pyramid: SA = 1/2 as + 3/2 sl a = altitude of the base triangle s = side of the triangle l = slant height of the pyramid.
Call the length of the base s and the slant height of one triangle l SA = s2 + 2sl
The answer is given below.
If you make a line from the top of the pyramid to the center of the base, you have the height of the pyramid. This meets at the midsegment of a line going across the base. Since the height of a pyramid is perpendicular with the base, get this: the height, a line of 1/2 the length of the base, and the slant height form a right triangle. So, you can use the Pythagorean Theorem! For example, if the base length is 6 and the height of the pyramid is 4, then you can plug them into the Pythagorean Theorem (a squared + b squared = c squared, a and b being the legs of a right triangle and c being the hypotenuse). 1/2 the length of the base would be 6 divided by 2=3. 3 squared + 4 squared = slant height squared. 9+16=slant height squared. 25= slant height squared. Slant height=5 units. You're welcome!
slant height of the pyramid Louvre in Paris=28 meters
It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.
The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.
120
There is not enough information to answer the question.
false
The slant height will be 25 cm
The surface area of a cone: SA = pi*r² + pi*r*s (r is radius, s is slant height) The surface area of a pyramid: SA = [1/2 * Perimeter * Slant Height] + [Base Area]
The height of the triangular face of a pyramid is called the slant height.
no
Such a pyramid cannot exist. If it is a regular pyramid with side length 8, its slant height MUST be less than 8. In fact, it is approx 6.39.
The surface area is a function of the height (or slant height) and the radius of the base. So, the slant height is a function of the surface area and the base-radius. Since the latter is unknown, the slant height cannot be calculated.