This is to do with the intermolecular forces in the two compounds. There are no hydrogen bonds between the molecules of either compound, since Br and I are not electronegative enough to polarise the molecules sufficiently. But since HI molecules contain more electrons than HBr, there are increased van der Waals forces in HI. For the same reason HBr has a higher boiling point than HCl, but HF has a higher boiling point than HCl, HBr or HI because of hydrogen bonding.
The element bromine is in the state of a liquid at room temperature (room temperature is roughly 20 degrees Celsius). This is because it's boiling point is 59 degrees Celsius, which is 39 degrees more then room temperature.
HBr In a chemical equation you would write it as HBr(aq).
This does not make a buffer because HBr is a STRONG acid, and for a buffer you need a WEAK acid and the salt of the acid.
Hydrogen bromide is covalent. Pure HBr has a melting point of -114.20C and a boiling point of -85.10C. The molecule has a dipole moment which is due to the poalr nature of the chemical bond. In water HBr is a strong acid, hydrobromic acid, and is pretty well completely dissocaiated.
HBr ok
HCL has a higher boiling point compared to HBr This is due to difference in electronegativity. H - 2.1 Cl - 3.0 Br - 2.8 The difference for HCl is 0.9, the difference for HBr is 0.7. The larger the difference in electronegavity means the stronger the bond. Large difference means greater attraction hence more energy is needed to overcome this bond.
Hydrogen fluoride has higher boiling point than hydrogen bromide ( HF 19.5 C HBr -66 C) because in hydrogen fluoride has two kinds of forces, one is hydrogen bonding and other is London dispersion forces. In Hydrogen bromide there are only london dispersion forces. These are weaker than hydrogen bonds therefore HF has the higher boiling pint.
Hydrobromic Acid (HBr) Melting point: -11 °C (47-49% w/w aq.) Boiling point: 122 °C at 700 mmHg (47-49% w/w aq.)
Yes, it is true: -85,1 0C at 1, 013 bar.
There is no hydrogen bonding in HBr and HI. The intermolecular forces are London dispersion forces- HI has more electrons, so more instantaneous induced dipole-dipole interaction- more intermolecular force- and therefore a higher boiling point.
HI has a higher boiling point because of the dipole-dipole Intermolecular forces as well as the dispersion forces, which become more evident with molecular weight, which will dominate over the dipole-dipole forces, so HCl has a lower boiloing point.
HBr has a lower melting point of -86.8 degrees C. HF has a melting point of -83 degrees C.
Water has the highest boiling point, as the hydrogen bonds between the molecules need more energy to break than the hdyrogen bonds in H2S, and H2Se, as Oxygen is much more electronegative than Sulphur of Selenium, so it makes the molecules more polar.
Ka = [H+].[Br-] / [HBr] However the value of this expression is very high, because HBr is a STRONG acid, meaning that much more than 99.9% of the HBr molecules in water are protolized (ionized), making [H+] and [Br-] equal to the original (added) HBr amount, and the [HBr]-value nearly zero.
H2o
actually HBr is stronger acid than HCl so i think you got something mixed up
yes it is, because HBr is a stronger acid than HCl, therfore, HBr will have a weaker conjugate base, Br, than HCl, Cl