Answer:
Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if:
a. Her father is colorblind
b. Her offpsring are colorblind
She may carry the colorblindness gene if:
a. Male family members (brothers, uncles, etc.) are colorblind
A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy)
So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring:
Xx (a normal girl who carries the colorblindness gene)
XY (a normal boy)
Xx (a normal girl who carries the colorblindness gene)
XY (a normal boy)
The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.