Yes, the reaction involving the solid is actually an individual step in the equation of the reaction between the solutions. If you were to add the change in enthalpy of the reaction with the solid NaOh to the change in enthalpy of the other step in the reaction (that's adding water and the NaOh pellets) you would find the sum equivalent to the change in enthalpy of the reaction involving the two solutions (this is supported by Hess's law). I suggest that you consider Hess's law for more information.
NO!!!! They are two different substances. Hydrochloric Acid has the formula 'HCl' Lime water is a suspension of calcoum hydroxide , whose formula is Ca(OH)2.
Method: titration with a standardized solution of sodium (or potassium) hydroxide.
HCl + NaOH -----> NaCl + H2O I hope it is correct
NaOH + HCl --> NaCl + H2O
A water solution of sodium chloride (NaCl) and soap.
NO!!!! They are two different substances. Hydrochloric Acid has the formula 'HCl' Lime water is a suspension of calcoum hydroxide , whose formula is Ca(OH)2.
The salt formed in this reaction is ammonium hydroxide.
CaCl2
Method: titration with a standardized solution of sodium (or potassium) hydroxide.
Method: titration with a standardized solution of sodium (or potassium) hydroxide.
Potassium Hydroxide(KOH) is a base (it is "basic"). An acid will neutralize a base. Acetic acid can be used to neutralize KOH. Baking soda is a base, so it will not work to neutralize KOH.
HCl + NaOH -----> NaCl + H2O I hope it is correct
NaOH + HCl --> NaCl + H2O
Hydrogen is released and sodium chloride&sodium hydroxide remain in solution.
0.0532
enthalpy change of solution=enthalpy change of hydration - enthalpy change of lattice
Hydrochloric acid: yellow color Sodium hydroxide: brown color Sugar: unchanged