Write a c program to find the sum of the digits of a number?

Answer 1

#include<iostream>

int sum_digits(int num, int base=10)

{

int sum=0;

while( num )

{

sum+=num%base;

num/=base;

}

return(sum);

}

int main()

{

int sum=sum_digits(42);

// assert( sum==6);

}

Answer 2

#include<stdio.h>

int sumOfDigit(int x){

int ans = 0;

while(x>0){

ans += (x%10);

x /= 10;

}

return ans;

}

int main(void){

printf("%d",sumOfDigit(12));

return 0;

}

Answer 3

if we have five digits then this may be the solution

#include <stdio.h>

int main(void)

{

int i,temp = 0;

printf("Enter a +ve 5 digit number :");

scanf("%d",&i);

if (( i <= 99999 ) && ( i > 9999 ))

{

printf(" %d",(i/10000) + 1);

printf(" %d",((( i/100) % 100)/10) + 1);

printf(" %d",(( i/100) % 10 ) + 1);

printf(" %d",((i % 100) / 10) + 1 );

printf(" %d",(i % 10) + 1);

}

else

printf("\n Pl.enter +ve five digit number");

return 0;

}

Answer 4

int main() {

int num, sum;

printf ("Enter a positive integer: ");

scanf ("%d", num);

sum = 0;

while (num>0) {

sum += num%10;

num/=10;

}

printf ("The sum of the digits is: %d\n", sum);

return 0;

}

Answer 5

for (digsum= 0; n!=0; digsum+=n%10, n/=10);