Program in c language to find sum of digits using recursion?

Answer 1

# include
void main()
{
int no,rem=0,sum=0,n; /*declaration*/
printf("Enter 2 digit number:");
scanf("%d",&no);
for(n=1;n<3;n++) /*conditions*/
{
rem=no%10; /*separation of digits using % and / */
sum=sum+rem;
no=no/10;
}
printf("sum=%d",sum);
}

Answer 2

/*this v'll work to obtain sum of 1st and last number of any number */

#include

int main()

{

int num,sum=0,i,fd,ld;

printf("enter the number);

scanf("%d",&num);

ld=n%10; //will get the last digit

while(num!=0)

{

fd=n;

n/10; //to get the 1st digit

}

sum=fd+ld; //add 1st n last digit

printf("\n sum of 1st n last digit is %d",sum)

}

Answer 3

#include<stdio.h>

int main()

{

int s,sum;

long num;

printf("enter the no:");

scanf("%ld",&num);

sum=num;

while(sum>10)

{

sum=0;

while(num!=0)

{

s=num%10;

sum=sum+s;

num=num/10;

}

num=sum;

}

printf("the single digit sum is :%d",sum);

return 0;

}

Answer 4

int Sum( int digits ) { if(digits < 10) return digits; return digits%10 + Sum(digits/10); }

Answer 5

Something like this:

http://codepad.org/ua952rap

Answer 6

#include

Void main()